Answer:
For a trapezium of height H, parallel side 1 X, and parallel side 2 Y, the area is:
A = (1/2)*H*(X + Y)
with this we can complete the table.
a)
Here we know:
X = 7cm
Y = 11cm
H = 6cm
Then: A = (1/2)*6cm*(7cm + 11cm) = 54 cm^2
b)
Here we know:
X = 8 m
Y = 10 m
A = 126 m^2
Then:
126 m^2 = 0.5*H*(8m + 10m)
126 m^2 = H*9m
126 m^2/9m = H = 14m
Then the height of this trapezoid is 14m
c)
Here we know:
X = 5mm
H = 8mm
A = 72 mm^2
Then:
72 mm^2 = 0.5*8mm*(5mm + Y)
72 mm^2 = 4mm*(5mm + Y)
72mm^2/4mm = 5mm + Y
18 mm = 5mm + Y
18mm - 5mm = Y
13 mm = Y
Then the parallel side 2 is 13 mm long.
F(x) = -5x - 4
g(x) = 6x - 7
f(x) + g(x) = (-5x-4) + (6x-7)
f(x) + g(x) = x - 11
Answer:
x = 1
Step-by-step explanation:
Given that y varies inversely as x then the equation relating them is
y = 
← k is the constant of variation
To find k use the condition y = 5 when x = 3
k = yx = 5 × 3 = 15, thus
y = 
← equation of variation
When y = 15 then
15 = ( multiply both sides by x )
15x = 15 ( divide both sides by 15 )
x = 1
Answer:
48000
Step-by-step explanation:
12000 students
4%
1 =annually
12×4×1= 48000
Answer:
2(x+3)
Hope u get it correct!!!
Step-by-step explanation:
