Answer:
x = - 
, x = 1
Step-by-step explanation:
Given
2x - 5 = - 3x² ( add 3x² to both sides )
3x² + 2x - 5 = 0 ← in standard form
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.
product = 3 × - 5 = - 15 and sum = + 2
The factors are - 3 and + 5
Use these factors to split the x- term
3x² - 3x + 5x - 5 = 0 ( factor the first/second and third/fourth terms )
3x(x - 1) + 5(x - 1) = 0 ← factor out (x - 1) from each term
(x - 1)(3x + 5) = 0 ← in factored form
Equate each factor to zero and solve for x
3x + 5 = 0 ⇒ 3x = - 5 ⇒ x = -
x - 1 = 0 ⇒ x = 1
Answer:
please add a link. I dont get the question you are trying to ask
Start from the point (0,0) and go up 4 spaces, then to the right 1, and put a dot. Continue doing this.
Brainliest Please!
Correct question is ;
Given the equation of the parabola x² = -36y
The focus of the parabola is:
Answer:
Option C - Focus = (0,-9)
Step-by-step explanation:
The equation of the parabola is:
x² = -36y
Thus, y = - x²/36
Using the vertex form,
y = a(x − h)² + k, to determine the values of a, h, and k.
We will have;
y = (-1/36)(x − 0)² + 0
Thus,
a = - 1/36
h = 0
k = 0
The distance (p) from the vertex to a focus of the parabola is gotten by using the following formula.
p = 1/4a
So, p = 1/(4*(-1/36))
p = - 1/(1/9)
p = -9
Now, The focus of a parabola can be found by adding p to the y-coordinate k if the parabola opens up or down.
Focus is (h, k+p)
Plugging in the relevant values, we have;
Focus = (0, (0 + (-9))
Focus = (0,-9)
