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3 years ago

What is the surface are of the triangle prism

Mathematics

1 answer:

stepladder [879]3 years ago

5 0

You can find the area of a triangular prism by putting it into a bet and finding the area of all sides then adding them together

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What is the slope of the line that passes through these two points? (-2, 4) (3, 4)

Rama09 [41]

Answer:

slope = 0

Step-by-step explanation:

calculate the slope m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (- 2, 4 ) and (x₂, y₂ ) = (3, 4 )

m = $\frac{4-4}{3-(-2)}$ = $\frac{0}{3+2}$ = $\frac{0}{5}$ = 0

7 0

2 years ago

Read 2 more answers

A contractor has been hired to install flooring for a bandstand in the shape of a circle that is 21 feet across. How many square

SOVA2 [1]

Answer:

A. 346.19 square feet.

Step-by-step explanation:

We have been given that a contractor has been hired to install flooring for a bandstand in the shape of a circle that is 21 feet across.

To find the square feet of flooring required, we will find area of circle.

Since the length across the circle is 21 feet, so radius of circle will be half of 21 feet.

$\text{Radius}=\frac{\text{21 feet}}{2}$

$\text{Radius}=\text{10.5 feet}$

$\text{Area of circle}=\pi r^2$

$\text{Area of circle}=\pi (\text{10.5 feet})^2$

$\text{Area of circle}=3.14*110.25\text{ feet}^2$

$\text{Area of circle}=346.185\text{ feet}^2$

$\text{Area of circle}\approx 346.19\text{ feet}^2$

Therefore, 346.19 square feet of flooring will be required.

3 0

3 years ago

Read 2 more answers

.In the Star Wars franchise, Yoda stands at only 66 centimeters tall. Suppose you want to see whether or not hobbits from the Lo

r-ruslan [8.4K]

Answer:

We conclude that the average height of hobbit is taller than Yoda.

Step-by-step explanation:

We are given that in the Star Wars franchise, Yoda stands at only 66 centimetres tall.

From a sample of 7 hobbits, you ﬁnd their mean height $\bar X$ = 80 cm with standard deviation s = 10.8 cm.

Let $\mu$ = average height of hobbit.

So, Null Hypothesis, $H_0$ : $\mu$ $\leq$ 66 cm {means that the average height of hobbit is shorter than or equal to Yoda}

Alternate Hypothesis, $H_A$ : $\mu$ > 66 cm {means that the average height of hobbit is taller than Yoda}

The test statistics that would be used here One-sample t test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n}}}$ ~ $t_n_-_1$

where, $\bar X$ = sample mean height = 80 cm

s = sample standard deviation = 10.8 cm

n = sample of hobbits = 7

So, test statistics = $\frac{80-66}{\frac{10.8}{\sqrt{7}}}$ ~ $t_6$

= 3.429

The value of t test statistics is 3.429.

Now, at 0.01 significance level the t table gives critical value of 3.143 for right-tailed test. Since our test statistics is more than the critical value of t as 3.429 > 3.143, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the average height of hobbit is taller than Yoda.

3 0

4 years ago

CAN SOMEONE MULTIPLY THIS PLEASE, ITS URGENT

____ [38]

Let's factorise it :

$\: {\qquad \dashrightarrow \sf ( {x}^{3} - 5)(x + 3) }$

$\: {\qquad \dashrightarrow \sf {x}^{3} (x + 3) + [-5(x + 3)] }$

Using Distributive property we get :

$\: {\qquad \dashrightarrow \sf {x}^{3} + {3x}^{3} + ( - 5x - 15) }$

$\: {\qquad \dashrightarrow \sf {x}^{3} + {3x}^{3} - 5x - 15 }$

$\: {\qquad \dashrightarrow \sf 4{x}^{3} - 5x - 15 }$

⠀

Therefore,

$\: {\qquad \dashrightarrow \sf ( {x}^{3} - 5)(x + 3) =4{x}^{3} - 5x - 15}$

8 0

2 years ago

How do I solve -2x > 6

vodomira [7]

I’m not the best with words but first you would have to treat the greater sign as a = sign. So..
-2x =6
/ /
-2 -2
X = -3
and then you would change the sign to a less than sign because you divided by a negative.

7 0

3 years ago