Out of the 52 cards in a deck, there are 13 clubs and 4 aces. The given situation is an inclusive event because out of the 4 aces there is one of them that is a club. The probability therefore, P(ace) + P(club) - P(inclusive event) Substituting gives, 4/52 + 13/52 - 1/52 = 4/13 The answer is letter C. 4/13.
