3 years ago

Can someone help me please?

Mathematics

1 answer:

taurus [48]3 years ago

4 0

Answer:

the only answer that makes sense would be the length

You might be interested in

Pierre stands on a level ground at the point P, 5 metres from O.

Zolol [24]

I think there is data that is missing. Please attach the drawing so that to help you

5 0

3 years ago

A plumber charges $25 for a service call, plus $50 per hour of service. (Linear Equation)

DochEvi [55]

Answer:

y=50x+25

y-interept=(0,25)

slope: 50

8 0

3 years ago

Find the area of the isosceles triangle.

kogti [31]

Answer:

The hight length : h

The base length : a

Apply the Pythagorean theorem in the right triangle :

h² = 13² - (10/2) = 144

h = √144 = 12 cm

S = (a x h)/ 2 = ( 10 x 12 )/2 = 60 cm²

Step-by-step explanation:

5 0

2 years ago

What is the simplified form of -(x-4) ? 0 A -X-4 B. -X+ 0 C. X+4 D. X-4

sertanlavr [38]

Hello you answer will be...... -x+4
let me know if I’m right

5 0

3 years ago

Sean b= 5,79; c= 10,4,el angulo A= 54,46°, el angulo C mide ?

Rzqust [24]

Answer:

$C \approx 91.732^{\circ}$

Step-by-step explanation:

(This exercise is presented in Spanish and for that reason explanation will be held in such language)

El lado restante se determina por la Ley del Coseno:

$a = \sqrt{b^{2}+c^{2}-2\cdot b\cdot c \cdot \cos A}$

$a = \sqrt{5.79^{2}+10.4^{2}-2\cdot (5.79)\cdot (10.4)\cdot \cos 54.46^{\circ}}$

$a \approx 8.466$

Finalmente, el angulo C se halla por medio de la misma ley:

$\cos C = - \frac{c^{2}-a^{2}-b^{2}}{2\cdot a \cdot b}$

$\cos C = -\frac{10.4^{2}-8.466^{2}-5.79^{2}}{2\cdot (8.466)\cdot (5.79)}$

$\cos C = -0.030$

$C \approx 91.732^{\circ}$

3 0

3 years ago