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2 years ago

the length of a rectagle is twice its width. if the perimeter of the rectangle is 36in, find its length and width

Mathematics

2 answers:

Leona [35]2 years ago

7 0

Answer:

6*2=12

if length is 12 half it would be 36

Aleks [24]2 years ago

7 0

Answer:

width = 6in

length = 12in

Step-by-step explanation:

If we call the width x, the length has to be 2x and so...

x + 2x + x + 2x = 36 (this can be simplified to ↓)

6x = 36 (if you divide both sides by 6...)

x = 6

This means that the width of the rectangle is 6in and so the length is 12in.

Hope this helps!

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Step-by-step explanation:

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3 years ago

Samantha needs 4/5 yard of fabric to make costumes for the school play. Write and solve and equation to find how many costumes s

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Step-by-step explanation:

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3 years ago

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3 years ago

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Dmitrij [34]

Answer:

The mid-point is (9,-9/2)

Step-by-step explanation:

You would use the mid-point formula for this

$(\frac{x_{2} +x_{1} }{2} , \frac{y_{2}+y_{1} }{2} )$

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2 years ago

Genius question: A long level railway bridge passes over a railroad track, which is 100 feet below it and at right angles to it.

nataly862011 [7]

Answer: <u>110 feet per second</u>

Step-by-step explanation:

In this problem we will assume that the car at 45 miles per hour is moving into the x direction with a high of 100 feet, and the train is going in the y direction, so they trajectories will made an angle of 90º.

Now we can calculate the speed of the trains in feet per second so:

$S1=\frac{45*5280}{3600}=66$

$S2=\frac{60*5280}{3600}=88$

So we can make a right triangle with sides 66 and 88 and the hypotenuse will be the rate that the trains will separate per second so:

$h=\sqrt{66^{2} +88^{2} } =\sqrt{4356+7744}$

$h=\sqrt{12100}=110$

Is important to have in mind that the initial high is not going to change how fast the trains will separate, however, if we are going to calculate the distance we should have it in the calculations.

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3 years ago