Question

I need help!!!! The square below has the given side lengths. x is positive

Answer 1

Answer:

See below, please

Step-by-step explanation:

This square

$3 {x}^{2} + 6x + 7 = 2 {x}^{2} - 2x + 27$

$(3 {x}^{2} - 2 {x}^{2} ) + (6x + 2x) + (7 - 27) = 0$

${x}^{2} + 8x - 20 = 0$

$(x + 10) \times (x - 2) = 0$

Hence,

$x1 = 2$

$x2 = - 10$

Because x is positive, So,

$x = 2$

Then we know

The length of one of the sides

$= 3 {x}^{2} + 6x + 7 = (3 \times {2}^{2}) + (6 \times 2) + 7 = (3 \times 4) + 12 + 7 = 31$

The area of the square

$= {31}^{2} = 961$

The perimeter of the square

$= 31 \times 4 = 124$

Answer 2

Answer:

Value of X: X=2

Length of One Side: 31

Area: 961u^2

Perimeter: perimeter = 124

Step-by-step explanation:

Set the sides equal to each other, simplify and then use quadratic equation. One result is positive and the other is negative, shape's sides have to be positive so use the positive value for X.