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kumpel [21]
2 years ago
15

I need help!!!! The square below has the given side lengths. x is positive

Mathematics
2 answers:
Allisa [31]2 years ago
7 0

Answer:

See below, please

Step-by-step explanation:

This square

3 {x}^{2}  + 6x + 7 = 2 {x}^{2}  - 2x + 27

(3 {x}^{2}  - 2 {x}^{2} ) + (6x  +  2x) + (7 - 27) = 0

{x}^{2}  + 8x - 20 = 0

(x + 10) \times (x - 2) = 0

Hence,

x1 =  2

x2 =  - 10

Because x is positive, So,

x = 2

Then we know

The length of one of the sides

= 3 {x}^{2}  + 6x + 7 = (3 \times  {2}^{2})  + (6 \times 2) + 7 = (3 \times 4) + 12 + 7 = 31

The area of the square

=  {31}^{2}  = 961

The perimeter of the square

= 31 \times 4 = 124

Hoochie [10]2 years ago
5 0

Answer:

Value of X: X=2

Length of One Side: 31

Area: 961u^2

Perimeter: perimeter = 124

Step-by-step explanation:

Set the sides equal to each other, simplify and then use quadratic equation. One result is positive and the other is negative, shape's sides have to be positive so use the positive value for X.

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What is the 7th term of the geometric sequence where a1 = -625 and a2 = 125
kykrilka [37]
Since the sequence is geometric, there is some constant r such that the sequence is recursively given by

a_n=ra_{n-1}

By this definition, you can recursively substitute into the right hand side the definition for a_{n-1},a_{n-2},\ldots to find an explicit formula for the nth term.

a_n=ra_{n-1}=r^2a_{n-2}=r^3a_{n-3}=\cdots=r^{n-1}a_1=-625r^{n-1}

You know the second term, which means you can find r:

a_2=-625r^{2-1}\implies125=-625r\implies r=-\dfrac15

So, the 7th term of the sequence is

a_7=-625\left(-\dfrac15\right)^{7-1}=-\dfrac1{25}
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3 years ago
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Answer:

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