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9 months ago

Is anyone able to solve this?

Mathematics

1 answer:

Olenka [21]9 months ago

4 0

Explanation:

To find x we need to find the unknown side that connects the two triangles using the Pythagorean theorem:

a² + b² = c² (c is always hypotenuse)

So:

a² + 6² = 9²

a² = 9² - 6²

a² = 81 - 36

a² = 45

a = sqrt45

Now we do the same thing for the other triangle:

x² + 5² = sqrt45²

x² + 25 = 45

x² = 20

x = 2√5 or 4.5...

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Just follow these steps:
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2 years ago

Please see the image and help with this homework problem. thank you!

dimulka [17.4K]

we have the function

$E=\sin \frac{\pi}{14}t$

Part a

For t=7

substitute in the given function

$\begin{gathered} E=\sin \frac{\pi}{14}7 \\ E=1 \end{gathered}$

For t=14

$\begin{gathered} E=\sin \frac{\pi}{14}14 \\ E=0 \end{gathered}$

For t=21

$\begin{gathered} E=\sin \frac{\pi}{14}21 \\ E=-1 \end{gathered}$

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$\begin{gathered} E=\sin \frac{\pi}{14}28 \\ E=0 \end{gathered}$

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$\begin{gathered} E=\sin \frac{\pi}{14}35 \\ E=1 \end{gathered}$

Observation: The values of E varies from -1 to 1, including the zero

Part B

Remember that

The Period goes from one peak to the next

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1 year ago

How do you subtract nega

sergey [27]

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3 years ago

Read 2 more answers

Determine the horizontal, vertical, and slant asymptotes: y=x2+2x-3/x-7

densk [106]

Answer:

vertical asymptote: x = 7
slant asymptote: y = x+9

Step-by-step explanation:

The vertical asymptotes are found where a denominator factor is zero (and there is no corresponding numerator factor to cancel it). Here, that is at x = 7.

There is no horizontal asymptote because the numerator is of higher degree than the denominator.

When you divide the numerator by the denominator, you get ...

y = (x +9) +60/(x -7)

Then when x gets large, the behavior is governed by the terms not having a denominator: y = x +9. This is the equation of the slant asymptote.

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