Answer:
you wrote the answer
Step-by-step explanation:
Answer:
a) 33.33%)
b) 135 minutes
c) 8.66 min
d) 50%
Step-by-step explanation:
a) the probability for a uniform distribution is
P(b<X<a) = (a-b)/(c-d) , where c and d are the maximum and minimum values
therefore the probability that the flight is more than 140 minutes ( and less than 150 since it is the maximum value)
P(140<X<150) = (a-b)/(c-d) = (150-140)/(150-120) = 10/30 = 1/3 (33.33%)
b) the mean (expected value) for a uniform probability distribution is
E(X) = (c+d)/2 = (120+150)/2 = 135 minutes
c) the standard deviation for a uniform probability distribution is
σ²(X)= (c-d)²/12 = (150-120)²/12 = 75 min²
σ = √75 min² = 8.66 min
b) following the same procedure as in a)
P(120<X<135) = (a-b)/(c-d) = (135-120)/(150-120) = 15/30 = 1/2 (50%)
6n−20=−2n+4(1−3n)
Simplify both sides of the equation.
−6n−20=−2n+4(1−3n)
−6n+−20=−2n+(4)(1)+(4)(−3n)(Distribute)
−6n+−20=−2n+4+−12n
−6n−20=(−2n+−12n)+(4)(Combine Like Terms)
−6n−20=−14n+4
−6n−20=−14n+4
Add 14n to both sides.
−6n−20+14n=−14n+4+14n
8n−20=4
Add 20 to both sides.
8n−20+20=4+20
8n=24
Divide both sides by 8.
8n/8 = 24/8
n=3
