Answer:
10%
Step-by-step explanation:
Given: CP of lemon is $600.
3/4 of lemon sold at 20% loss
Remaining lemon at 20% gain.
Considering the quantity of lemon remain constant.
Cost price of 3/4 of lemon= 
As given, 3/4 of lemon sold at 20% loss.
∴ Selling price of 
Selling price= 
Hence, selling price of 3/4 lemon is $360.
Now, the cost price of remaining lemon 
∴ The cost price of
As given, remaining 
∴ Selling price of 
Selling price of 
Hence, selling price of 1/4 lemon is $180
Loss\profit percent= 
∴ Loss\profit percent= 
Hence, the loss percentage is 10%
I can't see the whole problem
Answer:

Step-by-step explanation:
Since we are not given a midpoint, we use the Angle Addition Postulate:
156 = [x + 109] + [x + 53]
156 = 162 + 2x
-162 - 162
_______________
−6 = 2x
___ ___
2 2
−3 = x
[−3 + 53] + [−3 + 109] = 156
50 106
156 = 156 ☑
Therefore,
is a genuine statement.
I am joyous to assist you anytime.
X^2 + 4x + 8 = 0
( x + 2 ) ( x + 2 ) = 0
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