d =sqrt ((x2-x1)^2 +(y2-y1)^2)
sqrt((12-2)^2 +(7--3)^2)
sqrt(10^2+10^2)
sqt(100+100)
sqrt(200)
sqrt(100)sqrt(2)
10sqrt(2)
Choice B
Answer:
the solution of linear equation 4b + 6 = 2 - 6 + 4 is b = -2
Step-by-step explanation:
We need to solve the linear equation
4b + 6 = 2 - 6 +4
Adding constants
4b + 6 = 0
Adding -6 on both sides
4b + 6 -6 = 0 -6
4b = -6
Dividing with 4 on both sides
4b/4 = -6/4
b = -2
So, the solution of linear equation 4b + 6 = 2 - 6 + 4 is b = -2
Answer:
-1
Step-by-step explanation:
The mean is the sum of all values divided by the amount of values.
We take the sum of all the numbers:
-3 + -8 + 12 + -15 + 9
-11 + 12 + -15 + 9
1 + -15 + 9
10 + -15
-5
We then divide the sum by how many number we have (we are given 5 numbers):
-5/5 = -1
Therefore, our mean is equal to -1.
Answer:
rate of the plane in still air is 33 miles per hour and the rate of the wind is 11 miles per hour
Step-by-step explanation:
We will make a table of the trip there and back using the formula distance = rate x time
d = r x t
there
back
The distance there and back is 264 miles, so we can split that in half and put each half under d:
d = r x t
there 132
back 132
It tells us that the trip there is with the wind and the trip back is against the wind:
d = r x t
there 132 = (r + w)
back 132 = (r - w)
Finally, the trip there took 3 hours and the trip back took 6:
d = r * t
there 132 = (r + w) * 3
back 132 = (r - w) * 6
There's the table. Using the distance formula we have 2 equations that result from that info:
132 = 3(r + w) and 132 = 6(r - w)
We are looking to solve for both r and w. We have 2 equations with 2 unknowns, so we will solve the first equation for r, sub that value for r into the second equation to solve for w:
132 = 3r + 3w and
132 - 3w = 3r so
44 - w = r. Subbing that into the second equation:
132 = 6(44 - w) - 6w and
132 = 264 - 6w - 6w and
-132 = -12w so
w = 11
Subbing w in to solve for r:
132 = 3r + 3(11) and
132 = 3r + 33 so
99 = 3r and
r = 33
