Step-by-step explanation:
since in a triangle each side must be shorter than the sum of the other 2 sides (otherwise the end points cannot connect, and there is no triangle), the necessary inequality condition must be
side < 1 + 2 = 3
so,
side < 3
for a lower limit let's go through the cases
1 < 2 + side (is always true)
2 < 1 + side
1 < side (side must be larger than 1)
and again
side < 1 + 2 = 3
side < 3
so the full restriction for the third side is
1 < side < 3
For example you have the 52, and you have the 24, you look for a number that can go into both that is the largest possible for my example it would be 4 since no number greater can go into both, while 2 would be a option it would not be the greatest.
Y= 2x
Every hour 2 bags
Afer 1 hour. 2 bags
After 2 hours 4 bags
After 3 hours. 6 bagds
We can use a trig function to find the measure of angle T.
tan(T) = 18/13
Take the archtangent on both sides since we are searching for an angle.
arctan(tan T) = arctan(18/13)
T = 54.16°
The measure of angle T is 54.16°.
Answer:
'A' is true; theoretically, 50% of the data items reside between the first and third quartiles (40 and 67.5)
Step-by-step explanation:
Range is 84-28 which is 56
Median is 51
1.5 x Interquartile Range (IQR) = 1.5(67.5-40) which equals 41.25
Q1 is 40
Q1 - IQR = -1.25
Low outliers are below -1.25 - 41.25; there are not data items below -42
