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mixer [17]
3 years ago
5

Unpolarized light passes through two polarizers whose transmission axes are at an angle of 30.0 degrees with respect to each oth

er. What fraction of the incident intensity is transmitted through the polarizers?a.) 0.750b.) 0.866c.) 0.375d.) 0.627
Physics
1 answer:
Evgen [1.6K]3 years ago
6 0

Answer:

a) 0.750

Explanation:

When the unpolarized light passes through the first polarizer, it becomes polarized along the axis of transmission of the polarizer itself.

Then, the light passes through the second polarizer, whose axis of transmission is inclined by an angle \theta with respect to the direction of polarization of the light.

Calling I_0 the initial intensity of the light, the intensity of light passing through the second filter is

I=I_0 cos^2 \theta

where

\theta=30^{\circ}

Solving the formula for \frac{I}{I_0}, which is the fraction of the incident intensity transmitted through the second polarizer, we find

\frac{I}{I_0}=cos^2 \theta = cos^2 30^{\circ}=0.750

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Exactly one turn of a flexible rope with mass m is wrapped around a uniform cylinder with mass M and radius R.
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Answer:

\omega=\sqrt{\omega_0^2(\frac{M+m}{M})}

Explanation:

The rotational kinetic energy when the cylinder is with the rope is:

E_k=\frac{1}{2}I_c\omega_0^2+\frac{1}{2}I_r\omega_0^2

where we used the fact that both rope and cylinder hast the same w. This E_k must conserve, that is, E_k must equal E_k when the rope leaves the cylinder. Hence, the final w is given by:

E_{k1}=E_{k2}\\\\\frac{1}{2}I_c\omega_0^2+\frac{1}{2}I_r\omega_0^{2}=\frac{1}{2}I_c\omega^2\\\\\omega=\sqrt{\omega_0^2(\frac{I_c+I_r}{I_c})} (1)

For Ic and Ir we can assume that the rope is a ring of the same radius of the cylinder. Then, we have:

I_c=\frac{1}{2}MR^2\\\\I_r=mR^2

Finally, by replacing in (1):

\omega=\sqrt{\omega_0^2(\frac{M+m}{M})}

hope this helps!!

7 0
3 years ago
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A. 2 S O 2, gas, plus O 2, gas, in equilibrium with 2 S O 3, gas.


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Answer:

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Explanation:

Gravitational force between two objects of masses m_{1},  m_{2} kept at a distance r is given by the formula

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Here ,m_{1} = 2m

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3 years ago
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