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mixer [17]
3 years ago
5

Unpolarized light passes through two polarizers whose transmission axes are at an angle of 30.0 degrees with respect to each oth

er. What fraction of the incident intensity is transmitted through the polarizers?a.) 0.750b.) 0.866c.) 0.375d.) 0.627
Physics
1 answer:
Evgen [1.6K]3 years ago
6 0

Answer:

a) 0.750

Explanation:

When the unpolarized light passes through the first polarizer, it becomes polarized along the axis of transmission of the polarizer itself.

Then, the light passes through the second polarizer, whose axis of transmission is inclined by an angle \theta with respect to the direction of polarization of the light.

Calling I_0 the initial intensity of the light, the intensity of light passing through the second filter is

I=I_0 cos^2 \theta

where

\theta=30^{\circ}

Solving the formula for \frac{I}{I_0}, which is the fraction of the incident intensity transmitted through the second polarizer, we find

\frac{I}{I_0}=cos^2 \theta = cos^2 30^{\circ}=0.750

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Before CDs and cassette tapes, there were vinyl records. The most comon spun with an angular velocity of 33.3revolutionsperminut
sashaice [31]

Answer:

539.5°

Explanation:

33.3 revolutions per minute

1 revolution = 360°

1 minute = 60 seconds

hence

33.3 revs ----> 1 minute = 60 seconds

X revs -----------> 2.70 seconds

X = (33.3 x 2.7)÷60 = 1.4985 revolutions in 2.70 seconds

1.4985 revolutions = 1.4985 x 360 = 539.46

which is approximately 539.5°

7 0
3 years ago
A total charge of 9.0 mC passes through a cross-sectional area of a nichrome wire in 3.6s. The number of electrons passing throu
Setler79 [48]
<h2>Given :</h2>

  • total charge = 9.0 mC = 0.009 C

Each electron has a charge of :

1.6 \times 10 {}^{ - 19} \:  C

For producing 1 Cuolomb charge we need :

  • \mathrm{\dfrac{1}{1.6 \times 10 {}^{ - 19} } }

  • \dfrac{10 {}^{19} }{1.6}

  • \dfrac{10\times 10 {}^{19} }{16}

  • \dfrac{100 \times 10 {}^{18} }{16}

  • \mathrm{6.24 \times 10 {}^{18}  \:  \: electrons}

Now, for producing 0.009 C of charge, the number of electrons required is :

  • 0.009 \times 6.24 \times  {10}^{18}

  • 0.05616 \times 10 {}^{18}

  • \mathrm{5.616 \times 10 {}^{16}  \:  \: electons}

_____________________________

So, Number of electrons passing through the cross section in 3.6 seconds is :

\mathrm{5.616 \times 10 {}^{16} \:  \: electrons}

Number of electrons passing through it in 1 Second is :

  • \dfrac{5.616 \times  {10}^{16} }{3.6}

  • \mathrm{1.56 \times 10 {}^{16}  \:  \: electrons}

Now, in 10 seconds the number of electrons passing through it is :

  • 10 \times  \mathrm{1.56 \times 10 {}^{16}  \:  \: }

  • \mathrm{1.56 \times 10 {}^{17}  \:  \: electrons}

_____________________________

\mathrm{ \#TeeNForeveR}

6 0
3 years ago
The model of the atom has changed as scientists have gathered new evidence. Four models of the atom are shown below, but one imp
nexus9112 [7]

Answer: Dalton’s model

Explanation:

In the attached image we can see four atomic models labeled with four letters:

W represents the current and accepeted atomic model: a nucleus with an electron cloud, where the orbit and position of the electrons around the nucleus is defined by specific regions (associated with specific energy levels) where there is a greater probability of finding the electron at any given moment. It is important to note this model was improved by the works in quantum physics done by Louis de Broglie and Erwin Schrodinger.

X represents Rutherford's model (This model was proposed after Thomson's model). Ernest Rutherford conducted a series of experiments in order to corroborate Thomson's atomic model. However the results of the experiment led him to find out there is a concentration of charge in the atom's core (which was later called nucleus) surrounded by electrons.  This lead to a new atomic model, in which the atom has a positive charged nucleus surrounded by negative charged particles that move similar to the orbit of the planet around the Sun.

Y represents Thomson's model, also called  the <em>plum pudding</em> model. This scientific found out that atoms contain small subatomic particles with a negative charge (later called electrons). However, taking into consideration that at that time there was still no evidence of the atom nucleus, Thomson thought the electrons were immersed in the atom of positive charge that counteracted the negative charge of the electrons. Just like the raisins embedded in a pudding or bread.

Z represents Bohr's model. This model was proposed by the danish physicist Niels Bohr after Rutherford's model. In fact, this model was Rutherford's model with the following addition: electrons orbit the nucleus (like planets around the sun) in specific orbits at different energy levels around the nucleus.

So, the only missing model is <u>Dalton's model</u>, which was the first atomic model:  the atom represented as a solid, indestructible and indivisible mass. An idea that was already accepted by that time since the ancient Greeks.

4 0
3 years ago
Read 2 more answers
A physics book is thrown horizontally at a velocity of 5.0 m/s from the top of a cliff 78.4 m high. How long does the book take
xenn [34]

The book's vertical position in the air is

y=78.4\,\mathrm m-\dfrac12gt^2

where g=9.80\,\frac{\mathrm m}{\mathrm s}. It reaches the ground when y=0, at a time t such that

0=78.4\,\mathrm m-\dfrac12gt^2\implies t=4.00\,\mathrm s

So it takes the book 4 seconds to reach the bottom. The given initial velocity is irrelevant since it only has a horizontal component; vertically, the book is starting from rest.

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4 years ago
6A certain load and set of slings create a 20-degree angle between the load and each sling leg. Using a spreader for the same li
Otrada [13]

Solution:

The angle between the sling and the load is 20^{\circ}

So the  tension in each sling can be calculated as

Sin \theta = Mg => T = \frac{Mg}{2Sin\theta}

Sin \theta=> \frac{Mg}{2Sin 20^{\circ}}

Where    

M is the mass of the load

The Horizontal reaction on the sling will be inward.

After using the spreader, the new angle between sling and load is 60^{\circ}, the tension in the sling will be  

T= \frac{Mg}{2 Sin 60^{\circ}} = \frac{Mg}{2 Sin 20^{\circ}}

The tension will be same as before in the sling move away through the spreader at an angle more than 90 degree the horizontal force will act opposite and will be outward

5 0
3 years ago
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