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mixer [17]
3 years ago
5

Unpolarized light passes through two polarizers whose transmission axes are at an angle of 30.0 degrees with respect to each oth

er. What fraction of the incident intensity is transmitted through the polarizers?a.) 0.750b.) 0.866c.) 0.375d.) 0.627
Physics
1 answer:
Evgen [1.6K]3 years ago
6 0

Answer:

a) 0.750

Explanation:

When the unpolarized light passes through the first polarizer, it becomes polarized along the axis of transmission of the polarizer itself.

Then, the light passes through the second polarizer, whose axis of transmission is inclined by an angle \theta with respect to the direction of polarization of the light.

Calling I_0 the initial intensity of the light, the intensity of light passing through the second filter is

I=I_0 cos^2 \theta

where

\theta=30^{\circ}

Solving the formula for \frac{I}{I_0}, which is the fraction of the incident intensity transmitted through the second polarizer, we find

\frac{I}{I_0}=cos^2 \theta = cos^2 30^{\circ}=0.750

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CaHeK987 [17]

Answer:

Its length is measured to be 0.5 m

Explanation:

From theory of relativity (mass variation), we know that:

m = mo/√(1-v²/c²)

Where, m = relative mass

and, mo = rest mass

The momentum of stick while moving, will be:

P = mv

but, it is given in the form of rest mass as:

P = 2(mo)v

thus, by comparison;

2(mo)v = mv

using value of m from theory of relativity;

2(mo)v = (mo)v/√(1-v²/c²)

√(1-v²/c²) = 1/2     ______ eqn(1)

Now, for relativistic length (L), we have the formula from same theory of relativity;

L = (Lo)√(1-v²/c²)

The rest length (Lo) of meter stick is 1 m, and the remaining term on right side √(1-v²/c²), known as Lorentz Factor, can be given by eqn (1), as equal to 1/2.

Thus,

L = (1 m)(1/2)

<u>L = 0.5 m</u>

4 0
3 years ago
16. Calculate the mass in kg of an object that is being accelerated 12 m/s with a force of 654 N.
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(654m/s ) / (12m/s) = 54.5 kg.
3 0
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On Earth, the gravitational field strength is 10 N/kg. Calculate Ep for a 4 kg bowling ball have that is being held 2 m above th
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Answer:

80 J

Explanation:

Ep = mgh

Ep = (4 kg) (10 m/s²) (2 m)

Ep = 80 J

4 0
3 years ago
(4.56 x 10^-13)-(1.17 x 10^-13)
avanturin [10]
3.39 x 10^-13

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3 0
2 years ago
A heavy rope, 60 ft long, weighs 0.7 lb/ft and hangs over the edge of a building 140 ft high. (a) How much work W is done in pul
Marina CMI [18]

Answer:

5880lb-ft of work is done

Explanation:

The length of the heavy rope is given as 60ft and the weight per length is 0.7lb/ft.

Therefore, the total weight of the heavy rope is

60×0.7 =42lb.

The work done in pulling the heavy rope to the top of the building is w = Fd.

Where

F is force is measured in pounds;42lb

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3 years ago
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