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mixer [17]
4 years ago
5

Unpolarized light passes through two polarizers whose transmission axes are at an angle of 30.0 degrees with respect to each oth

er. What fraction of the incident intensity is transmitted through the polarizers?a.) 0.750b.) 0.866c.) 0.375d.) 0.627
Physics
1 answer:
Evgen [1.6K]4 years ago
6 0

Answer:

a) 0.750

Explanation:

When the unpolarized light passes through the first polarizer, it becomes polarized along the axis of transmission of the polarizer itself.

Then, the light passes through the second polarizer, whose axis of transmission is inclined by an angle \theta with respect to the direction of polarization of the light.

Calling I_0 the initial intensity of the light, the intensity of light passing through the second filter is

I=I_0 cos^2 \theta

where

\theta=30^{\circ}

Solving the formula for \frac{I}{I_0}, which is the fraction of the incident intensity transmitted through the second polarizer, we find

\frac{I}{I_0}=cos^2 \theta = cos^2 30^{\circ}=0.750

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Many fitness programs include weight training, which A. can be used in place of aerobic exercise, when done regularly. B. helps
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The answer would be C) because weight lifting is used to increase your muscular strength, and that's why you try and add more weight during sessions, so it's not too easy for you and you can build a higher endurance.
6 0
3 years ago
Low-pressure areas tend to ____ before occluding and ____ after occluding
alexgriva [62]

Out of the following given choices;

a. decelerate; accelerate

b. accelerate; decelerate

c. stop; accelerate

d. decelerate; stop

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4 0
4 years ago
What is projectile motion​
Georgia [21]

pls follow me

Explanation:

A projectile is an object upon which the only force is gravity. The horizontal motion of the projectile is the result of the tendency of any object in motion to remain in motion at constant velocity. Due to the absence of horizontal forces, a projectile remains in motion with a constant horizontal velocity.

4 0
3 years ago
Read 2 more answers
55. (III) A uniform circular plate of radius 2R has a circular hole of radius R cut out of it. The center of the smaller circle
Aleksandr [31]

Answer:

P = 0.27R from the center

Explanation:

Given,

The radius of the uniform circular plate, R = 2R

The radius of the hole, r = R

The center of the smaller circle from the center is, d = 0.8R

The center of mass of a circular disc with a hole in it given by the formula

                               P = dr²/R² - r²

Where P is the distance from the center of mass located in the line joining the two centers opposite to the hole.

Substituting the given values in the above equation,

                               P = 0.8R x R² / 4R² - R²

                                  = 0.27R³/R²

                                  = 0.27R

Hence the center of mass of plate is at a distant  P = 0.27R from the center

6 0
3 years ago
A firecracker in a coconut blows the coconut into three pieces. Two pieces of equal mass fly off south and west, perpendicular t
Lisa [10]

Explanation:

Let us assume that piece 1 is m_{1} is facing west side. And, piece 2 is m_{2} facing south side.

Let m_{1} \text{and} m_{2} = m and m_{3} = 2m. Hence,

        2mv_{3y} = m(21)

          v_{3y} = \frac{21}{2}

                     = 10.5 m/s

2mv_{3x} = m(21)

          v_{3x} = \frac{21}{2}

                     = 10.5 m/s

  v_{3} = \sqrt{v^{2}_{3x} + v^{2}_{3y}}

              = \sqrt{(10.5)^{2} + (10.5)^{2}}

              = 14.84 m/s

or,          = 15 m/s

Hence, the speed of the third piece is 15 m/s.

Now, we will find the angle as follows.

          \theta = tan^{-1} (\frac{v_{3y}}{v_{3x}})

                      = tan^{-1}(\frac{10.5}{10.5})

                      = tan^{-1} (45^{o})

                      = 45^{o}

Therefore, the direction of the third piece (degrees north of east) is north of east.

5 0
4 years ago
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