Answer:
G M m / R^2 = m v^2 / R centripetal force equals gravitational force
1/2 m v^2 = G M m / R = KE rearranging the above equation
T = 2 pi R / v time for one revolution (period)
T^2 = 4 pi^2 R^2 / v^2
From the very first equation v^2 = G M / R
so T^2 = 4 pi^2 R^3 / (G * M)
<span>B.Extrinsic motivation </span>
<h3><u>Answer;</u></h3>
= 2868 Newtons
<h3><u>Explanation;</u></h3>
Centripetal force is a force that acts on an object or a body in circular path and is directed towards the center of the circular path.
Centripetal force is given by the formula;
mv²/r ; where m is the mass of the body, r is the radius of the circular path and v is the velocity of a body;
mass = 65 kg, velocity = 15 m/s and r = 5.1 m
Therefore;
Centripetal force = (65 × 15²)/ 5.10
= 2867.65 Newtons
= 2868 N
Answer:
The force is
Explanation:
Given that,
Diameter = 7.55 mm
Intensity of light = 3.87 kW/m²
Angle = 19.9°
Intensity of absorbed light
![I_{1}=E^2\sin^2\theta](https://tex.z-dn.net/?f=I_%7B1%7D%3DE%5E2%5Csin%5E2%5Ctheta)
Intensity of incoming light
![I=E^2](https://tex.z-dn.net/?f=I%3DE%5E2)
Ratio of intensities
![\dfrac{I_{1}}{I}=\dfrac{E^2\sin^2\theta}{E^2}](https://tex.z-dn.net/?f=%5Cdfrac%7BI_%7B1%7D%7D%7BI%7D%3D%5Cdfrac%7BE%5E2%5Csin%5E2%5Ctheta%7D%7BE%5E2%7D)
![I_{1}=I\sin^2\theta](https://tex.z-dn.net/?f=I_%7B1%7D%3DI%5Csin%5E2%5Ctheta)
Relation between intensity and power
...(I)
The power is
....(II)
From equation (I) and (II)
![I_{1}=\dfrac{F\times c}{A}](https://tex.z-dn.net/?f=I_%7B1%7D%3D%5Cdfrac%7BF%5Ctimes%20c%7D%7BA%7D)
![F=\dfrac{I\sin^2\theta\times A}{c}](https://tex.z-dn.net/?f=F%3D%5Cdfrac%7BI%5Csin%5E2%5Ctheta%5Ctimes%20A%7D%7Bc%7D)
Put the value into the formula
![F=\dfrac{3.87\times10^{3}\sin^2(19.9)\times\pi\times(\dfrac{7.55\times10^{-3}}{4})^2}{3\times10^{8}}](https://tex.z-dn.net/?f=F%3D%5Cdfrac%7B3.87%5Ctimes10%5E%7B3%7D%5Csin%5E2%2819.9%29%5Ctimes%5Cpi%5Ctimes%28%5Cdfrac%7B7.55%5Ctimes10%5E%7B-3%7D%7D%7B4%7D%29%5E2%7D%7B3%5Ctimes10%5E%7B8%7D%7D)
Hence, The force is
Answer: An AU equals the distance between Earth and the Sun; a parsec
equals the angle between an object's apparent positions when viewed
from two different locations.
Explanation:
Light year is the distance light travels in one Earth year. 1 light year is equal to
.
An astronomical unit (AU) is the average distance between the earth and the sun. An AU is approximately 150 million km.
A parsec is the distance at which one astronomical unit subtends an angle of one second of arc. 1 parsec is equal to 20600 AU.