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3 years ago

Find X: 6x=36 A) 4 B) 10 C) -1 D) 6

Mathematics

2 answers:

Nimfa-mama [501]3 years ago

7 0

Answer: $x=6$

Divide both sides by 6

$6x/6=36/6\\x=6$

svetoff [14.1K]3 years ago

5 0

Answer:

$6x = 36 \\ \frac{6x}{6} = \frac{36}{6} \\ x = 6$

hope this help you....

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PLEASE HELP!

liberstina [14]

The correct answer to this question is this one:

Regular triangle with :

bearing from the western station = 90° - 40° = 50°

bearing from the eastern station.= 90° + 22° = 112°

-> the third angle : 18°

Thus the distance from balloon to the western station:

x/ sin112 = 165 / sin 18

5 0

4 years ago

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Volunteer drivers are needed to bring 24 students to the championship baseball game. Drivers either have cars, which can seat

natima [27]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Is y=-4+3x^2 maximum of minimum

mixer [17]

Answer:

minimum

Step-by-step explanation:

Given a quadratic in standard form : y = ax² + bx + c : a ≠ 0

Whether the function is maximum or minimum can be determined by consideration of the sign of the coefficient a

• If a > 0 then minimum

• If a < 0 then maximum

For y = - 4 + 3x² the value of a is 3 > 0

Hence y = - 4 + 3x² is a minimum

7 0

4 years ago

An ellipse has vertices at (0, #17) and foci at (0, ±15). Write the equation of the ellipse in standard form. Graph the ellipse.

Lunna [17]

ANSWER

$\frac{ {x}^{2} }{ 64 } + \frac{ {y}^{2} }{ 289 } = 1$

See attachment for the graph

EXPLANATION

The standard equation of the vertical ellipse with center at the origin is given by

$\frac{ {x}^{2} }{ {b}^{2} } + \frac{ {y}^{2} }{ {a}^{2} } = 1$

where

${a}^{2} \: > \: {b}^{2}$

The ellipse has its vertices at (0,±17).

This implies that:a=±17 or a²=289

The foci are located at (0,±15).

This implies that:c=±15 or c²=225

We use the following relation to find the value of b²

${a}^{2} - {b}^{2} = {c}^{2}$

$\implies \: 289 - {b}^{2} = 225$

$- {b}^{2} = 225 - 289$

$- {b}^{2} = - 64$

${b}^{2} = 64$

We substitute into the formula for the standard equation to get:

$\frac{ {x}^{2} }{ 64 } + \frac{ {y}^{2} }{ 289 } = 1$

4 0

3 years ago

[(√4 + 3)2 – 9] / (√9 – 1)3 * 2

Ket [755]

Answer:

$\frac{1}{12}$

Step-by-step explanation:

$\frac{(\sqrt{4} + 3)2 - 9}{ (\sqrt{9} - 1)3 * 2}=\frac{(2+3)2-9}{(3-1)6}=\frac{10-9}{2*6}=\frac{1}{12}$

8 0

3 years ago