Large sphere's radius = R,
small sphere's radius = r, R = 8r
surface area of a sphere (SA) = 4×pi×radius^2
So what we need is the SA of the larger in terms of the smaller sphere, so if:
SA (of R) = 4×pi×R^2, then plug in "8r" for "R"...
SA = 4×pi×(8r)^2 = 4×3.14×64r^2
SA = 12.57×64r^2 = 804 r^2
Therefore the SA of the larger sphere is 804 times the SA of the smaller sphere.
I hope that makes sense!
Answer:
30.3m^2
Step-by-step explanation:
I started off by finding the area of the semi circle. The formula πr^2 divided by 2. The radius of the circle is 2 because it is half of the diameter which is 4. So π(2)^2 divided by 2 is 6.3.
Next I broke apart the the shape into a rectangle and a triangle for simplicity sake. So doing this I had to know where to cut and if you look at the top of the figure it shows 2m for the length at the top. So I put a vertical line there. Thus changing the 10m on the bottom to a 8m section and a 2m section. So the rectangle's area will be the length times the height which is 2x4=8.
The triangle's area can be found with the equation BH/2 and we the 8 base we found and a height of 4 it is 8x4/2. Which ends up as 16.
Finally you add up all three area's that you found 8+16+6.3=30.3
Answer:
Step-by-step explanation:
1. Using the point of intersections, we use the substitution method to find the coordinates of the line parallel to 
substituting the value of y in 
:
substituting x=-1 in y= -4-5x:
(upon solving, you should get this)
2. Using y=mx+c and making y the subject of the formula 2x-y-9=0 and using the coordinate we found earlier, we will find the equation of the parallel line. (We make y the subject of the formula to find the gradient)
-1= 2 x 1 +c
-3=c
