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3 years ago

Can anyone help me with this question, i dont really understand how to do pls help me

Mathematics

1 answer:

irina [24]3 years ago

3 0

there you goo :)) on the chain up on the left from 3 to 48 they keep multiplying by 2, and the other one, they keep subtracting by 7

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HELP PLZ ASAP whats the least common denominator if 1/8, 5/12, and 7/18 A.216 B.108 C.72 D.48

yanalaym [24]

Answer:

LCD = 72

Equivalent Fractions with the LCD

1/8 = 9/72

5/12= 30/72

7/18 = 28/72

Solution:

Rewriting input as fractions if necessary:

1/8, 5/12, 7/18

For the denominators (8, 12, 18) the least common multiple (LCM) is 72.

LCM(8, 12, 18)

Therefore, the least common denominator (LCD) is 72.

Calculations to rewrite the original inputs as equivalent fractions with the LCD:

1/8 = 1/8 × 9/9 = 9/72

5/12 = 5/12 × 6/6 = 30/72

7/18 = 7/18 × 4/4 = 28/72

6 0

3 years ago

Read 2 more answers

Help me please!!! 30 points! :)

kicyunya [14]

$\frac{625 {(5xy)}^{ - 3} }{ {(5x)}^{2} {y}^{7} } \: = \: 625 \times \frac{1}{ {(5xy)}^{3} } \times \frac{1}{ {(5x)}^{2} {y}^{7} } \: = \: 625 \times \frac{1}{125 {x}^{3} {y}^{3} } \times \frac{1}{25 {x}^{2} {y}^{7} } \: = \: \frac{1}{5 {x}^{5} {y}^{10} }$

3 0

3 years ago

The web logs of a certain website show that the average number of hits in an hour is 75 with a standard deviation equal to 8.6.

Wittaler [7]

Answer:

a) There is a 10.75% probability of observing less than 60 hits in an hour.

b) The 99th percentile of the distribution of the number of hits is 95.21 hits.

c) There is a 24% probability of observing between 80 and 90 hits an hour

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.

In this problem, we have that

The web logs of a certain website show that the average number of hits in an hour is 75 with a standard deviation equal to 8.6, so $\mu = 75, \sigma = 8.6$ .

a) What’s the probability of observing less than 60 hits in an hour? Use the normal approximation

This is the pvalue of Z when X = 60. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{60 - 75}{8.6}$

$Z = -1.74$

$Z = -1.74$ has a pvalue of 0.1075. This means that there is a 10.75% probability of observing less than 60 hits in an hour.

b) What’s the 99th percentile of the distribution of the number of hits?

What is the value of X when Z has a pvalue of 0.99.

Z = 2.35 has a pvalue of 0.99

$Z = \frac{X - \mu}{\sigma}$

$2.35 = \frac{X - 75}{8.6}$

$X - 75 = 20.21$

$X = 95.21$

The 99th percentile of the distribution of the number of hits is 95.21 hits.

c) What’s the probability of observing between 80 and 90 hits an hour?

This is the pvalue of the zscore of X = 90 subtracted by the pvalue of the zscore of X = 80.

For X = 90

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{90 - 75}{8.6}$

$Z = 1.74$

$Z = 1.74$ has a pvalue of 0.95907

For X = 80

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{80 - 75}{8.6}$

$Z = 0.58$

$Z = 0.58$ has a pvalue of 0.71904

There is a 0.95907 - 0.71904 = 0.24003 = 24% probability of observing between 80 and 90 hits an hour

6 0

3 years ago

Eight less than a number is no more than 14 and no less than 5

GaryK [48]

If you would like to transform the following phrase into a math expression, you can do it like this:

8 less than a number is no more than 14 and no less than 5
a number ... n
8 less ... - 8
no more than 14 .... < 14
no less than 5 ... > 5

Now you just have to put this together: 5 < n - 8 < 14
If 5 and 14 are included: 5 <= n - 8 <= 14

7 0

3 years ago

Goals and purpose of the BIA – unique to your scenario b. Summary of Findings – business functions and assessment c. Prioritizat

tangare [24]

Answer:

Prioritizations – critical, major, and minor classifications is correct option

8 0

4 years ago

Can anyone help me with this question, i dont really understand how to do pls help me ​

Can anyone help me with this question, i dont really understand how to do pls help me