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3 years ago

Which expression is equivalent to x^2-10x+24

Mathematics

1 answer:

Brut [27]3 years ago

4 0

Answer:

(x-4)(x-6)

Step-by-step explanation:

By factorization, x^2-10x+24 can be written in the form (x-4)(x-6). Thus the roots of the quadratic equation are x= 4 and 6 respectively.

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PLZ HELP I BEGGG 20 POINTS!!!!!!!

Roman55 [17]

Answer:

i belive its 100

Step-by-step explanation:

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3 years ago

The object depicted by the force diagram is

lubasha [3.4K]

Answer:

a) At rest

Step-by-step explanation:

25N+25N=50N

therefore, 50N is applied from both the sides

So, 50N - 50N = 0

the, net value is zero, here.

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3 years ago

One number is 1/4 of another number. The sum of the two numbers is 5. Find the two numbers. Use a comma to separate your answer

masha68 [24]

Answer: 1, 4

Step-by-step explanation:

Number #1 = x
Number #2 = $\frac{1}{4} x$

$\frac{1}{4} x+x=5\\\\\frac{1}{4} x+\frac{4}{4} x=5\\\\\frac{5}{4} x=5\\\\5x=4*5\\5x=20\\x=4$

Number #1 = x = 4
Number #2 = $\frac{1}{4} x$ = $\frac{1}{4} *4=\frac{4}{4} =1$

6 0

2 years ago

Write the standard form of the equation of the circle of radius r=6 and center (h,k) = (0,0).

Mama L [17]

Answer:

x²+y²=36

Step-by-step explanation:

any circle with center at (0,0)

has the equation of the form

x²+y²=r²

here r is radius r=6

so the answer

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3 years ago

In the game of blackjack played with one deck, a player is initially dealt 2 different cards from the 52 different cards in the

Volgvan

Answer:

$P =4.83\%$

Step-by-step explanation:

First we calculate the number of possible ways to select 2 cards an ace and a card of 10 points.

There are 4 ace in the deck

There are 16 cards of 10 points in the deck

To make this calculation we use the formula of combinations

$nCr=\frac{n!}{r!(n-r)!}$

Where n is the total number of letters and r are chosen from them

The number of ways to choose 1 As is:

$4C1 = 4$

The number of ways to choose a 10-point letter is:

$16C1 = 16$

Therefore, the number of ways to choose an Ace and a 10-point card is:

$4C1 * 16C1 = 4 * 16 = 64$

Now the number of ways to choose any 2 cards from a deck of 52 cards is:

$52C2 =\frac{52!}{2!(52-2)!}$

$52C2 = 1326$

Therefore, the probability of obtaining an "blackjack" is:

$P = \frac{4C1 * 16C1}{52C2}$

$P = \frac{64}{1326}$

$P = \frac{32}{663}$

$P =0.0483$

$P =4.83\%$

4 0

3 years ago

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