All categories

3 years ago

Prove the identity sin4x=2sin2xcos2x

2 answers:

7 0

Ok so think of it this way:
sin4x=sin2(2x), and lets say that 2x=a
By the double angle theorem, we know that sin2a=2sin(a)cos(a)
So substitute 2x for a, and there you go!

Musya8 [376]3 years ago

5 0

There is a trig identity called the sum of 2 angles for sin its
sin(a+b)=sin(a)cos(b)+cos(a)(sin(b)

You will need to use it. So in your question split the 4x in 2 equal parts 2x and 2x

sin(4x)=sin(2x+2x)

Now using the expansion above you will get

sin(2x+2x)=sin(2x)×cos(2x)+cos(2x)×sin(2x)

And it will simplify to

2sin(2x)cos(2x)

I hope this helps you! Good luck :)

You might be interested in

Need help with this art please

olga2289 [7]

This question should be answered with a ruler you have to measure them in mill meter and then put the numbers into the correct place for example
240 mm is with the hundreds section
And 57 is in the tens section
And more but don’t use the numbers i gave you they are only for examples
Hope it helps❤️

4 0

3 years ago

HELP ASAP PLEASE!!!

PilotLPTM [1.2K]

Answer:

Step-by-step explanation:

The range is the y values of the function from the least to the greatest. To find it find the furthest point up and down. Draw a horizontal line from the point to the y-axis to identify the y value. Here the function extends from -3 to 6. So the range is $-3\leq y\leq 6$ .

6 0

3 years ago

Temperature transducers of a certain type are shipped in batches of 50. A sample of 58 batches was selected, and the number of t

andrew11 [14]

Answer:

a) X Freq. Rel Freq.

__________________________

0 7 (7/58) = 0.121

1 10 (10/58)=0.172

2 13 (13/58) =0.224

3 14 (14/58)=0.241

4 6 (6/58)=0.103

5 3 (3/58)=0.052

6 3 (3/58)=0.052

7 1 (1/58) =0.017

8 1 (1/58)=0.017

_________________________

Total 58 1.00

b) $\frac{7+10+13+14+6}{58}= \frac{50}{58}=0.862$

Step-by-step explanation:

Assuming this question: Temperature transducers of a certain type are shipped in batches of 50. A sample of 60 batches was selected, and the number of transducers in each batch not conforming to design specifications was determined, resulting in the following data:

2,1,2,4,0,1,3,2,0,5,3,3,1,3,2,4,7,0,2,3,

0,4,2,1,3,1,1,3,4,2,3,2,2,8,4,5,1,3,1,

5,0,2,3,2,1,0,6,4,2,1,6,0,3,3,3,6,2,3

(a) Determine frequencies and relative frequencies for the observed values of x = number of nonconforming transducers in a batch. (Round your relative frequencies to three decimal places.)

For this case first we order the dataset on increasing way and we got:

0 0 0 0 0 0 0

1 1 1 1 1 1 1 1 1 1

2 2 2 2 2 2 2 2 2 2 2 2 2

3 3 3 3 3 3 3 3 3 3 3 3 3 3

4 4 4 4 4 4

5 5 5

6 6 6

And we can construct the following table:

X Freq. Rel Freq.

__________________________

0 7 (7/58) = 0.121

1 10 (10/58)=0.172

2 13 (13/58) =0.224

3 14 (14/58)=0.241

4 6 (6/58)=0.103

5 3 (3/58)=0.052

6 3 (3/58)=0.052

7 1 (1/58) =0.017

8 1 (1/58)=0.017

_________________________

Total 58 1.00

(b) What proportion of batches in the sample have at most four nonconforming transducers? (Round your answer to three decimal places.)

For this case this proportion would be:

$\frac{7+10+13+14+6}{58}= \frac{50}{58}=0.862$

4 0

3 years ago

Eduardo is filing his federal income tax return with the 1040EZ form, and he received two W-2 forms, with the federal income tax

Illusion [34]

I just had this question.... the answer is $4930 on APEX

8 0

3 years ago

Which of the following coordinates is located in Quadrant I?

oee [108]

Answer:

(4,6)

Step-by-step explanation:

quadrant 1 always has positive coordinates so the only one with all positive coordinates is (4,6)

5 0

2 years ago