The function that models the graph is given as:
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more numbers and variables.
The equation shown in the graph represents a piecewise function. Hence:
From the line through the point (-8, 4) and (-2, 2), the equation is f(x) = -(1/3)x + 4/3
From the curve through the point (-2, 2) and (0, 6), the equation is f(x) = -x² + 6
From the line through the point (0, 6) and (4, 6), the equation is f(x) = -6
From the line through the point (4, 6) and (7, 9), the equation is f(x) = x + 2
The function that models the graph is given as:
Find out more on equation at: brainly.com/question/2972832
#SPJ1
Answer:
Buddie
Buddie should enter on line 6 of the income section:
capital gains or losses that he incurred for the past year.
Step-by-step explanation:
Line 6 asks about the capital gains or losses from the past year so that the AGI total could be obtained before deductions are made. Where Line 6 is filled, there are some other forms that will accompany it, like Schedule D and 1099-B or 1099-S forms, which record the capital gains or losses. All capital gains that are not excludable must be stated for income tax purpose.
Hi There!
Answer: c. 7
Why: 84 / 7 = 12 and 49 / 7 = 7
Hope This Helps :)
Answer: M'(2, - 5), L'(-2, -5), j'(-4, - 1)
Step-by-step explanation:
When we do a reflection over a given line, the distance between all the points (measured perpendicularly to the line) does not change.
The line is y = 1.
Notice that a reflection over a line y = a (for any real value a) only changes the value of the variable y.
Let's reflect the points:
J(-4, 3)
The distance between 3 and 1 is:
D = 3 - 1 = 2.
Then the new value of y must also be at a distance 2 of the line y = 1
1 - 2 = 1
The new point is:
j'(-4, - 1)
L(-2, 7)
The distance between 7 and 1 is:
7 - 1 = 6.
The new value of y will be:
1 - 6 = -5
The new point is:
L'(-2, -5)
M(2,7)
Same as above, the new point will be:
M'(2, - 5)
Answer:
x ~0.9
Step-by-step explanation:
To solve for (x) in the given right triangle, use the trigonometric ratios, which are the following,

Each of the sides of a triangle is named with respect to the given angle. In this problem, one is given the side opposite to the given angle, and the side adjacent to it. Use the ratio of tangent (tan) to solve for the unknown side.

Manipulate the equation so that it is solved for (x),

x ~ 0.859