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3 years ago

PLEASE HELP ASAP! MATH

Mathematics

1 answer:

Lubov Fominskaja [6]3 years ago

7 0

Answer:

Step-by-step explanation:

A.AAS

∠TSU=∠RQU

∠TUS=∠RUQ

TU=RU

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HI HELP ME W MATH PLSS!!

4vir4ik [10]

Answer:

a) 79.6

b) 437.8

Step-by-step explanation:

First, you have to do 318.4/4 to find the rate she goes in the duration of an hour. The rate is 79.6, which means she travels at a rate of 79.6 kilometers per hour.

Then, you have to find the distance she takes to travel in 5.5 hours, so you have to do 5.5*79.6 which is 437.8.

So, Hannah travels 437.8 kilometers in 5.5 hours.

6 0

3 years ago

Help I need the answers

jolli1 [7]

240
/ \
5 48
/ \
6 8
/ \ / \
3 2 4 2

7 0

3 years ago

Read 2 more answers

How many sides does a regular polygon have if each exterior angle measures 30 degree

Nataly [62]

As the exterior angles always add up to 360, you can find the number of sides by dividing 360 by the measure of your exterior angle, 30. This gives you 360/30=12, meaning your polygon has 12 sides.

5 0

3 years ago

At the north campus of a performing arts school, 30% of the students are music majors. At the south campus, 70% of the stude

Ivenika [448]

Answer:

The north campus had 600 students (180 music majors)

The south campus had 400 students (280 music majors)

Step-by-step explanation:

x = number of students at the north campus before the merger

If the total of students for the two school is given as 1000, so:

(1000 - x) = number of students at the south campus before the merger.

The equation for music major is:

0,3x + 0,7(1000-x) = 0,46(1000)

0,3x + 700 - 0,7x = 460

0,3x - 0,7x = 460 - 700

- 0,4x = -240

x = -240/-0,4

x = 600 -----> total number of students at the north campus

600*(0,3) = 180 music majors at the north

100 - 600 = 400 ------> total number of students at the south campus

400*(0,7) = 280------>music majors at the south

4 0

3 years ago

The distance d of a particle moving in a straight line is given by d(t) = 2t3 + 5t – 2, where t is given in seconds and d is mea

Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

Given the distance, d(t) of a particle moving in a straight line at any time t is:

$d(t) = 2t^3 + 5t - 2, $ where t is given in seconds and d is measured in meters.$

To find an expression for the instantaneous velocity v(t) of the particle at any given point in time, we take the derivative of d(t).

$v(t)=\dfrac{d}{dt}\\\\v(t) =\dfrac{d}{dt}(2t^3 + 5t - 2) =3(2)t^{3-1}+5t^{1-1}\\\\v(t)=6t^2+5$

The correct option is C.

6 0

3 years ago