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pickupchik [31]

2 years ago

5

If a puzzle measures 14 in x 16 in, how many inches of frame for the puzzle?

1 answer:

dedylja [7]2 years ago

4 0

There will be 224 inches :)

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Evaluate the expression when p= -24 and q = 4.

Talja [164]

$(2 \times - 24) \div - 4$
which comes out as 12

3 0

3 years ago

A boat travelling upstream goes 36 kilometers in 6 hours. If the return trip takes only 3 hours, what is the speed (in kilometer

mr_godi [17]

11 kilometer per hour

8 0

3 years ago

12. On a table there were 16 dimes and quarters. The value of the coins was

7nadin3 [17]

6 quarters and 10 dimes

6 0

3 years ago

the sum of 3 decimal numbers is 6. Exactly one of the numbers is less than 1 what could those numbers be.

kati45 [8]

There are infinitely many solutions to this problem (which is why it asks what could those numbers be), so you just have to make one up!

Start with the first sentence.
x + y + z = 6.0

Now one of those numbers has to be less than 1. I'll choose x. And I'll choose a random number, say, 0.7.

0.7 + y + z = 6.0

Now I'll subtract 0.7 from both sides to see what y and z have to add up to.

0.7 + y + z - 0.7 = 6.0 - 0.7
y + z = 5.3

Now I'll choose a random number for y that's less than 5.3.

2.6 + z = 5.3

And subtract 2.6 from both sides to find z.

2.6 + z - 2.6 = 5.3 - 2.6
z = 2.7

And now we have our numbers!
x = <u>0.7</u>
y = <u>2.6</u>
z = <u>2.7</u>

3 0

3 years ago

What is the area of the composite figure

kati45 [8]

To solve this we will divide the given composite figure into three figures. The three figures will be 2 squares and 1 rectangle. Let's find their areas and add them!

$\boxed{ \sf \: area \: of \: square =side ^{2} }$

Side 3 metre

$\rm \implies \: area = 3 ^{2}$

$\rm \implies9$

<em>Thus, The area of 1st square is 9m²...</em>

The area of second square will be also 9m², because the sides of both squares are equal.

<h3>Now area of the reactangle⤵️</h3>

Length = 6m
Breadth = 7+3=10m

$\sf \: area \: of \: rectangle = length \times breadtg$

$\tt \dashrightarrow \: area = 10 \times 3$

$\tt \dashrightarrow \: area = 30m ^{2}$

<em>Thus, The area of rectangle is 30m²....</em>

Now, Add area of all the figures to get the total area.

$\bf \:total \: area = 9 + 9 + 30 \\ \bf= 48m {}^{2}$

<h3><em>Therefore, The total area of the composite figure is 48m²...~</em></h3>

8 0

2 years ago