Answer:
y=t−1+ce
−t
where t=tanx.
Given, cos
2
x
dx
dy
+y=tanx
⇒
dx
dy
+ysec
2
x=tanxsec
2
x ....(1)
Here P=sec
2
x⇒∫PdP=∫sec
2
xdx=tanx
∴I.F.=e
tanx
Multiplying (1) by I.F. we get
e
tanx
dx
dy
+e
tanx
ysec
2
x=e
tanx
tanxsec
2
x
Integrating both sides, we get
ye
tanx
=∫e
tanx
.tanxsec
2
xdx
Put tanx=t⇒sec
2
xdx=dt
∴ye
t
=∫te
t
dt=e
t
(t−1)+c
⇒y=t−1+ce
−t
where t=tanx
Answer: y<x-1
Step-by-step explanation:
So first we have to find the blue line. y=mx+b is the equation. For slope it is 0--1 which is 1 and 1-0 which is 1 so the slope is just one or x now we need to find the y intercept which is just -1. So y<(is less than)x-1! Hope this helps :)
Step-by-step explanation:
First solve for y
given equation is 3x-2y ≥ 12
subtract 3x on both sides of the equation which would result with: -2y ≥ 12-3x
divide by -2 on both sides of the equation, flip the sign to ≤ because you are dividing by a negative, then you should get the result y<u> </u><u>≤</u><u> </u>-6 + 3x/2 (should look like a fraction)
y-intercept is at -6
slope is 3/2 (or three halves)
start at -6 on the y-axis, go up 3 across 2 and plot your point, keep repeating when going up and down the graph
3.4(x+1.58)= - 11.288
Step 1: Distribute 3.4 to the numbers inside the parentheses (x+1.58)
3.4x + (3.4×1.58)= - 11.288
3.4x + 5.372 = -11.288
Step 2: Bring 5.372 to the right side by subtracting it to both sides
3.4x + (5.372 - 5.372 ) = (-11.288 - 5.372)
3.4x + (0) = (-16.66)
3.4x = -16.66
Step 3: Isolate x by dividing 3.4 to both sides
x = -4.9
Hope this helped!
6+5=11
or
6+5=?
It shows we originally have 6 and now have 5 more having a total of 11
