Answer:
The radius, r₂, of the ball that uses one-half the amount of rubber coating used to cover the 16-inch ball is approximately 4.66 inches
Step-by-step explanation:
The dimension of the ball with known radius = 16-inch
The surface area of the ball with 16-inch radius = 4×π×r² = π·D² = π×16² = 804.24772 in.²
Given that the ball uses one-half the rubber material coating used to cover the 16-inch ball, we have the surface area of the ball = 804.24772 in.²/2 = 402.12386 in.²
The radius, r₂ of the new ball is found as follows;
402.12386 in.² = 4×π×r₂²
r₂² = 402.12386 in.² /(4×π) ≈ 32
r₂ = √32 = 4·√2 ≈ 4.66 inches
The radius, r₂, of the ball that uses one-half the amount of rubber coating used to cover the 16-inch ball ≈ 4.66 inches.
Answer:
Step-by-step explanation:
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Answer:
3/20
Step-by-step explanation:
1/4 of 3/5= 3/20
hope its clear
Answer:
6x³ - 4x² - 8x - 16
Step-by-step explanation:
Step 1: Distribute the 2x
6x³ + 8x² + 8x
Step 2: Distribute the -4
-12x² - 16x - 16
Step 3: Combine the 2 distributions
6x³ + 8x² + 8x - 12x² - 16x - 16
Step 4: Combine like terms
6x³
8x² - 12x² = -4x²
8x - 16x = -8x
-16
Step 5: Rewrite
6x³ - 4x² - 8x - 16
