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Ipatiy [6.2K]
2 years ago
14

Find the area of a triangle 4cm height 6cm base​

Mathematics
1 answer:
Amanda [17]2 years ago
3 0

Answer:

12cm²

Step-by-step explanation:

Area of triangle =1/2×h×b

1/2×4×6

2×6

12cm²

hope dis helps!!!!!

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rewrite the polynomial 2y^2+ 6y^3-11-17y^4+8y^5 in the standard form also find its degree and coefficient of y^4
OleMash [197]

Answer:

The standard form is  8 y ⁵ - 17 y⁴ + 6 y³ +2 y² - 11

The degree of given polynomial is '5'

the co-efficient of  y⁴  is '-17'

Step-by-step explanation:

Given standard form 2 y²+ 6 y³-11-17 y⁴+8 y⁵

<em>The form ax² + b x + c is called the standard form of the quadratic expression of 'x'.This is second degree standard form of polynomial.</em>

<em>The form ax⁵ + b x⁴ + c x³ +d x² +ex +f  is called the standard form of the quadratic expression of 'x'.This is fifth degree standard form of polynomial</em>

now Given polynomial is  2 y²+ 6 y³-11-17 y⁴+8 y⁵

The standard form is

                                8 y ⁵ - 17 y⁴ + 6 y³ +2 y² - 11

<u><em>Conclusion</em></u>:-

<em>The degree of given polynomial is '5'</em>

<em>The co-efficient of  y⁴  is '-17'</em>

<em>   </em>

5 0
3 years ago
What is the radius of a circle whose area is 36 cm2
blsea [12.9K]

Answer:

your answer should be 6! :)

7 0
3 years ago
mile is going to give buddys dads company 5 hour and not a minute more. what part of the day is he giving them written as a frac
cluponka [151]

The fraction of the time given in a day is 1/288

Given the following parameters

  • The minute that mile gave his buddy = 5minuts

We are to get the fraction of this time in a day.

Convert 1 day to minute

  • 1 day = 24 hrs * 60 mins
  • 1 day = 1440 minuts

Fraction = 5/1440

Fraction = 1/288

Hence the fraction of the time given in a day is 1/288

Learn more on fractions here: brainly.com/question/78672

7 0
2 years ago
Trapezoid QRST is graphed on the set of axes below.
Marta_Voda [28]

Answer:

  (C) reflection on y = -x

Step-by-step explanation:

There are vertices on the x-axis, the y-axis, and the line y=x (point Q(3, 3)), so reflection on any of those lines will result in a point being invariant. The only line of reflection among the choices given that does not contain a vertex of the figure is y = -x.

  reflection on y = -x will give no invariant points

7 0
2 years ago
Barron's reported that the average number of weeks an individual is unemployed is 18.5 weeks. Assume that for the population of
Ket [755]

Answer:

A) The sampling distribution for a sample size n=50 has a mean of 18.5 weeks and a standard deviation of 0.849.

B) P = 0.7616

C) P = 0.4441

Step-by-step explanation:

We assume that for the population of all unemployed individuals the population mean length of unemployment is 18.5 weeks and that the population standard deviation is 6 weeks.

A) We take a sample of size n=50.

The mean of the sampling distribution is equal to the population mean:

\mu_s=\mu=18.5

The standard deviation of the sampling distribution is:

\sigma_s=\dfrac{\sigma}{\sqrt{n}}=\dfrac{6}{\sqrt{50}}=0.849

B) We have to calculate the probability that the sampling distribution gives a value between one week from the mean. That is between 17.5 and 19.5 weeks.

We can calculate this with the z-scores:

z_1=\dfrac{X_1-\mu}{\sigma/\sqrt{n}}=\dfrac{17.5-18.5}{6/\sqrt{50}}=\dfrac{-1}{0.8485}=-1.179\\\\\\z_2=\dfrac{X_2-\mu}{\sigma/\sqrt{n}}=\dfrac{19.5-18.5}{6/\sqrt{50}}=\dfrac{1}{0.8485}=1.179

The probability it then:

P(|X_s-\mu_s|

C) For half a week (between 18 and 19 weeks), we recalculate the z-scores and the probabilities:

z=\dfrac{X-\mu}{\sigma/\sqrt{n}}=\dfrac{18-18.5}{6/\sqrt{50}}=\dfrac{-0.5}{0.8485}=-0.589

P(|X_s-\mu_s|

5 0
3 years ago
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