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creativ13 [48]
3 years ago
12

Okay so I think I got it right, I just need someone to check over it.

Mathematics
2 answers:
Paladinen [302]3 years ago
6 0

Answer:

yes

Step-by-step explanation:

alexira [117]3 years ago
4 0

Answer:

Yes, from what I learned its correct.

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Charra [1.4K]
34 is larger than 3, so 34.653
4 0
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21 ten thousands + 18 ones + 60 hundreds
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21,618.........................
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Amanda is using wire to construct a triangle for an art project. She has 4 inches of blue wire and
belka [17]

Answer: 8

Step-by-step explanation:

4 is the base. 8 are the sides

6 0
3 years ago
The average daily jail population in the United States is 706,242. If the distribution is normal and the standard deviation is 5
Karolina [17]

a. The probability that on a randomly selected day, the jail population

is greater than 750,000 is 20.1%

b. The probability that on a randomly selected day, the jail population is

between 600,000 and 700,000 is 43.2%

Step-by-step explanation:

The given is:

1. The average daily jail population in the United States is 706,242

2. The distribution is normal and the standard deviation is 52,145

3. We need to find the probability that on a randomly selected day,

    the jail population is greater than 750,000

4. We need to find the probability that on a randomly selected day,

    the jail population is between 600,000 and 700,000

a.

At first find z-score

∵ z = (x - μ)/σ, where x is the score, μ is the mean and σ is the standard

   deviation

∵  x = 750,000 , μ = 706,242 and σ = 52,145

∴ z = \frac{750,000-706,242}{52,145} ≅ 0.84

Use the normal distribution table of z to find the area to the right of

the z-value

∵ The corresponding area to z-score of 0.84 is 0.79955

- But we are interested in x > 750,000, we need the area to the

  right of z-score

∴ P(x > 750,000) = 1 - 0.79955 = 0.2005

∴ P(x > 750,000) = 0.2005 × 100% = 20.1%

The probability that on a randomly selected day, the jail population is

greater than 750,000 is 20.1%

b.

We will find z-score for 600,000 < x < 700,000

∵ z = \frac{600,000-706,242}{52,145} ≅ -2.04

∵ z = \frac{700,000-706,242}{52,145} ≅ -0.12

Use the normal distribution table of z to find the area between

the two z-values

∵ The corresponding area to z-score of -2.04 is 0.02068

∵ The corresponding area to z-score of -0.12 is 0.45224

- To find P(600,000 < x < 700,000) subtract the two values above

∴ P(600,000 < x < 700,000) = 0.45224 - 0.02068 = 0.4316

∴ P(600,000 < x < 700,000) = 0.4316 × 100% = 43.2%

The probability that on a randomly selected day, the jail population is

between 600,000 and 700,000 is 43.2%

Learn more:

You can learn more about z-score in brainly.com/question/7207785

#LearnwithBrainly

5 0
3 years ago
Please help I don’t get it
lidiya [134]

Answer:

4.718592

Step-by-step explanation:

To get to -14.4 from 18 you multiply 18 x 0.8

Repeat that until you get to the 7th term

18 (1st)

18 x 0.8 = -14.4 (2nd)

-14.4 x 0.8 = 11.52 (3rd)

11.52 x 0.8 = 9.216 (4th)

9.216 x 0.8 = 7.3728 (5th)

7.3728 x 0.8 = 5.89824 (6th)

5.89824 x 0.8 = 4.718592 (7th)

3 0
3 years ago
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