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Anna11 [10]
2 years ago
11

Can someone help me out? I can't understand this shape. (Explanation also please). I'll mark brainliest

Mathematics
1 answer:
Tanya [424]2 years ago
8 0

The surface area of the rectangular prism is 46m²

<h3>How to find surface area of a rectangular prism?</h3>

  • length = 4m
  • width = 2.5m
  • height = 2m

Surface area of a rectangular prism = 2(width×length + height×length + height×width)

SA = 2(wl + hl + hw)

= 2(2.5×4 + 2×4 + 2×2.5)

= 2(10 + 8 + 5)

= 2(23)

= 46m²

Therefore, the surface area of a rectangular prism is 46m²

Learn more about surface area:

brainly.com/question/16519513

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Use this information to answer the questions. University personnel are concerned about the sleeping habits of students and the n
Oksanka [162]

Answer:

z=\frac{0.554 -0.5}{\sqrt{\frac{0.5(1-0.5)}{377}}}=2.097  

p_v =P(Z>2.097)=0.018  

If we compare the p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of  students reported experiencing excessive daytime sleepiness (EDS) is significantly higher than 0.5 or the half.

Step-by-step explanation:

1) Data given and notation

n=377 represent the random sample taken

X=209 represent the students reported experiencing excessive daytime sleepiness (EDS)

\hat p=\frac{209}{377}=0.554 estimated proportion of students reported experiencing excessive daytime sleepiness (EDS)

p_o=0.5 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is higher than 0.5:  

Null hypothesis:p\leq 0.5  

Alternative hypothesis:p > 0.5  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.554 -0.5}{\sqrt{\frac{0.5(1-0.5)}{377}}}=2.097  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>2.097)=0.018  

If we compare the p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of  students reported experiencing excessive daytime sleepiness (EDS) is significantly higher than 0.5 or the half.

6 0
3 years ago
How to work out 270 ÷ 30
tresset_1 [31]

Answer:

270 ÷ 30 = 9

Step-by-step explanation:

9x3=27

90x3 = 270

27 ÷ 3 = 9

270 ÷ 30 = 9

90 x 3 = 270

30 x 9  = 270

8 0
3 years ago
Solve for x and y please, will give brainliest
Inessa [10]
X is 57
That means y is 36.

Sorry, I’m gonna try not explain it because I’m rlly bad at explaining and all I’m going to do is confuse you even more...
8 0
3 years ago
Read 2 more answers
A bag contains 3 blue and 2 green marbles. What is the probability of drawing a blue marble folowed by a green marble, without r
nadya68 [22]

3 out of 5 percent chance

8 0
3 years ago
A local grocery store decides to offer a free piece of fresh fruit (banana or apple) to all shoppers in the produce department.
xxMikexx [17]

The generalization that can be made from this study is that: Given the choice of a banana or an apple, twice as many shoppers will select an apple.

<h3>How to arrive at the generalization.</h3>

More of the shoppers are said to select an apple from the group of shoppers who are to but either banana or apple.

Those buying an apple are two times the people buying the banana, hence we can conclude that twice as many shoppers would choose the apple over banana.

Read more on probability here: brainly.com/question/24756209

#SPJ4

3 0
2 years ago
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