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2 years ago

Please help. Are they parallel?

Mathematics

1 answer:

Serga [27]2 years ago

4 0

Answer:

yes

Step-by-step explanation:

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What is 120 divided by20

anzhelika [568]

Answer:

Step-by-step explanation:

120/20=5

6 0

2 years ago

Read 2 more answers

-6 - (-8) + 6 = <br> What is the value?

qaws [65]

Answer:

The answer is 8

Step-by-step explanation:

use order of operations.

*remember that there is an understood -1 in -(-8). this can also be written as -1(-8)*

$-6-(-8)+6\\-6+8+6\\2+6\\8$

hope this helps!

8 0

2 years ago

Does anyone know how to answer this question I'm having a lot of trouble with it?

Helen [10]

Answer:

h = $\frac{2A}{(b+c)}$

Step-by-step explanation:

Formula for the area of a trapezoid is,

Area (A) = $\frac{1}{2}(b+c)h$

Here b and c are the bases and 'h' is the height of the trapezoid.

2A = $2[\frac{1}{2}(b+c)h]$

2A = (b + c)h

$\frac{2A}{(b+c)}=h$

Therefore, formula for the height of the trapezoid will be,

h = $\frac{2A}{(b+c)}$

5 0

2 years ago

What does the point (1,8) mean in this situation?

sesenic [268]

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▹ Answer

<em>There are 8 chocolate chips in one pancake.</em>

▹ Step-by-Step Explanation

The x is labeled as Number of Pancakes.

The y is labeled as Number of Chocolate Chips

Therefore, the 1 represents the pancakes and the 8 represents the amount of chocolate chips per pancake. This would be stated as:

There are 8 chocolate chips in one pancake.

Hope this helps!

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Brainliest is greatly appreciated!

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7 0

3 years ago

Read 2 more answers

Find the value of kk for which the constant function x(t)=kx(t)=k is a solution of the differential equation 5t3dxdt+2x−2=05t3dx

uranmaximum [27]

Given the differential equation

$5t^3 \frac{dx}{dt} +2x-2=0$

The solution is as follows:

$5t^3 \frac{dx}{dt} +2x-2=0 \\ \\ \Rightarrow5t^3 \frac{dx}{dt} =2-2x \\ \\ \Rightarrow \frac{5}{2-2x} dx= \frac{1}{t^3} dt \\ \\ \Rightarrow \int {\frac{5}{2-2x} } \, dx = \int {\frac{1}{t^3}} \, dt \\ \\ \Rightarrow- \frac{5}{2} \ln(2-2x)=- \frac{1}{2t^2} +A \\ \\ \Rightarrow\ln(2-2x)= \frac{1}{5t^2} +B\\ \\ \Rightarrow2-2x=Ce^{\frac{1}{5t^2}} \\ \\ \Rightarrow 2x=Ce^{\frac{1}{5t^2}}+2 \\ \\ \Rightarrow x=De^{\frac{1}{5t^2}}+1$

3 0

2 years ago