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andrey2020 [161]
3 years ago
5

Please help. Are they parallel?

Mathematics
1 answer:
Serga [27]3 years ago
4 0

Answer:

yes

Step-by-step explanation:

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What is the missing numerator and denominator?
Drupady [299]

Answer:

the missing numerator is 4 and denominator is 4

8/14 In simpliest form is 4/7

Step-by-step explanation:

4/14+4/14=8/14

8 divded by 2=4 14 divded 2=7

7 0
3 years ago
I had $88. then i earned $29 walking dogs. after I spent money for concert tickets, I have $74 remaining. estimate how much mone
klemol [59]

Answer:

$43

Step-by-step explanation:

88+29=117

117-74=43

You Spent $43 For The Concert.

7 0
4 years ago
Read 2 more answers
What is the sum of the geometric series in which a1 = 4, r = 3, and an = 324?
olganol [36]
\bf n^{th}\textit{ term of a geometric sequence}\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
a_1=4\\
r=3\\
a_n=324
\end{cases}
\implies 
324=4(3)^{n-1}
\\\\\\
\cfrac{324}{4}=3^{n-1}\implies 81=3^{n-1}\implies 3^4=3^{n-1}\implies 4=n-1
\\\\\\
\boxed{5=n}\\\\

\bf -------------------------------\\\\
\qquad \qquad \textit{sum of a finite geometric sequence}\\\\
S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
a_1=4\\
r=3\\
n=5
\end{cases}
\\\\\\
S_5=4\left( \cfrac{1-3^5}{1-3} \right)\implies S_5=4\left(\cfrac{1-243}{-2}  \right)

and surely you know how much that is.
8 0
3 years ago
At a baseball game, a vender sold a combined total of 104 sodas and hot dogs. the number of sodas sold was three times the numbe
Reil [10]
You have to set up a system of equations

x+y=104
3x-y=104

Sodas = 78
Hotdogs = 26
7 0
4 years ago
In what situation might you have to calculate the surface area of volume of a solid?
Digiron [165]
One application of volume is determining the density of an object. Assume the object is made of a pure element (eg: gold). If we know the volume (v) of the object, and we know the mass (m), then we can use the formula D = m/v to figure out the density D. Knowing the volume is also handy to determine if the object can fit into a larger space or not. Another application is figuring out how much water is needed to fill up the inner space of the 3D solid (assuming it's hollow on the inside).

The surface area is handy to figure out how much material is needed to cover the outer surface. This material can be paint, paper, metal sheets, or whatever you can think of really. A good example is wrapping a present and the assumption is that there is no overlap. 
8 0
3 years ago
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