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2 years ago

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Two sides of a parallelogram are 5.8m and 8.2m long. Find the perimeter

1 answer:

Alex17521 [72]2 years ago

5 0

Answer:

5.8+5.8+8.2+8.2=28m

Step-by-step explanation:

If you want to find the PERIMETER you just need to add up the length of all of the sides. No multiplication needed. Just add the numbers. Don’t forget that there are multiple sides so even though only two are labeled dont forget to add every single side that the shape has.

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The new pool cover is 35 feet long and 13 feet wide with the overhang.

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Answer:

455

Step-by-step explanation:

multiply the width by the length

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3 years ago

Justin used 3/4 of a gallon of paint on 3/4 of a wall. How many gallons does he need for one wall?

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2 years ago

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Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.

loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>

$x^ax^b = x^{(a+b)}$
$\dfrac{x^a}{x^b} = x^{(a-b)}$
$(a^a)^b =x^{(a\times b)}$
$(xy)^a = x^ay^a$

$x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4$

The solution of the expression is $\dfrac{4x^4}{y^6}$ .

<h2>Explanation</h2>

Given to us

$(16x^8y^{12})^{\frac{1}{2}}$

Solution

We know that 16 can be reduced to $2^4$ ,

$=(2^4x^8y^{12})^{\frac{1}{2}}$

Using identity $(xy)^a = x^ay^a$ ,

$=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}$

Using identity $(a^a)^b =x^{(a\times b)}$ ,

$=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})$

Solving further

$=2^2x^4y^{-6}$

Using identity $\dfrac{x^a}{x^b} = x^{(a-b)}$ ,

$=\dfrac{2^2x^4}{y^6}$

$=\dfrac{4x^4}{y^6}$

Hence, the solution of the expression is $\dfrac{4x^4}{y^6}$ .

Learn more about Exponentiation:

brainly.com/question/2193820

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2 years ago

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kvasek [131]

Im not sure i understand the question, but i think 25/7

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3 years ago

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Solve by factoring:<br> 5t=t ^2

elena-14-01-66 [18.8K]

Answer:

t=0 and t=5

Step-by-step explanation:

5t = t^2

Subtract 5t from each side

5t-5t = t^2 -5t

0= t^2 -5t

Factor out a t

0= t(t-5)

Using the zero product property

t=0 and t-5 =0

t=0 and t-5+5=0+5

t=0 and t=5

7 0

2 years ago