Given that Z is the centroid of a triangle RST. This means that Z is the point of intersection of the three medians of the triangle.
So,W is the midpoint of RSV is the midpoint of RTWe are given that:RV = 4x + 3 and VT = 2x + 9
Since V is the midpoint, then:RV = VT4x + 3 = 2x + 94x - 2x = 9 - 32x = 6x = 3
Now put the value of x in WS = 5x-1WS = 5x-1WS = 5(3) - 1 WS = 15 - 1 = 14WS = 14
Since W is the midpoint of RS, therefore RW = WSand WS = 14Therefore:
RW = 14
Answer is 12 to your question
Answer:
4 ways (WW-BB-WB-BW)
Step-by-step explanation:
Answer:
As y = mx + c (standard form)
Thus relating the equation , we get
m = 1
c = -6
If they're integers, that means they can't be fractions (such as 15/2 and 2).
So the only couples of integers that, when multiplied, result in 15 are:
1 and 15
5 and 3.
(there are no other possibilities as both 5 and 3 are not divisible further).
The smaller of the two sums (15+1; 5+3) is 5+3=8.
The least possible sum of a and b is 8.
