Cos77.cos88 - sin77.cos2

Write 23 in significant notation

SOVA2 [1]

*I think you meant scientific notation.*

23 in scientific notation would be 2.3 x 10^1.

5 0

3 years ago

Read 2 more answers

Which of the following represents the difference between ten and a number is the sum of eight and a number"?

Alona [7]

9514 1404 393

Answer:

(c) 10 -N = 8 +N

Step-by-step explanation:

The difference between 10 and a number is (10 -N).

The sum of 8 and a number is (8 +N).

In this context, "is" means "equals," so we have ...

10 -N = 8 +N

7 0

3 years ago

Hot dogs come in packages of 8. Hot dog buns come in packages of 12. If Grace wants

TEA [102]

If one package of hot dogs buns is 12 than she need 2 packages

3 0

3 years ago

Three men are trying to hold a ferocious lion still for the veterinarian. The lion, in the center,is wearing a collar with three

Andre45 [30]

The answer
<span>the third rope to counterbalance Sam and Charlie is F
and vectF +vectF1 +vectF2 =vect0
let's consider axis
y'y </span>vectF = -F
vectF 1= F1cos60
vectF 2= F2cos45
-F = -F1cos60-F2co45
so F= F1cos60+F2co45= 350x0.5+400x0.7=457.84 pounds

4 0

3 years ago

A box contains 24 transistors,4 of which are defective. If 4 are sold at random,find the following probabilities. i. Exactly 2 a

zavuch27 [327]

SOLUTION

This is a binomial probability. For i, we will apply the Binomial probability formula

i. Exactly 2 are defective

Using the formula, we have

$\begin{gathered} P_x=^nC_x\left(p^x\right?\left(q^{n-x}\right) \\ Where\text{ } \\ P_x=binomial\text{ probability} \\ x=number\text{ of times for a specific outcome with n trials =2} \\ p=\text{ probability of success = }\frac{4}{24}=\frac{1}{6} \\ q=probability\text{ of failure =1-}\frac{1}{6}=\frac{5}{6} \\ ^nC_x=\text{ number of combinations = }^4C_2 \\ n=\text{ number of trials = 4} \end{gathered}$

Note that I made the probability of being defective as the probability of success = p

and probability of none defective as probability of failure = q

Exactly 2 are defective becomes the binomial probability

$\begin{gathered} P_x=^4C_2\times\lparen\frac{1}{6})^2\times\lparen\frac{5}{6})^{4-2} \\ P_x=6\times\frac{1}{36}\times\frac{25}{36} \\ P_x=\frac{25}{216} \\ =0.1157 \end{gathered}$

Hence the answer is 0.1157

(ii) None is defective becomes

$\begin{gathered} \lparen\frac{5}{6})^4=\frac{625}{1296} \\ =0.4823 \end{gathered}$

hence the answer is 0.4823

(iii) All are defective

$\begin{gathered} \lparen\frac{1}{6})^4=\frac{1}{1296} \\ =0.00077 \end{gathered}$

(iv) At least one is defective

This is 1 - probability that none is defective

$\begin{gathered} 1-\lparen\frac{5}{6})^4 \\ =1-\frac{625}{1296} \\ =\frac{671}{1296} \\ =0.5177 \end{gathered}$

Hence the answer is 0.5177

3 0

1 year ago

Cos77.cos88 - sin77.cos2​

Cos77.cos88 - sin77.cos2