Question

13. What is the equation in standard form of the circle

Answer 1

The standard form of a circle shows the center and the radius

The equation of the circle in standard form is (x + 5)^2 + (y - 4)^2 = 57

How to determine the equation?

The standard equation of a circle is:

(x - a)^2 + (y - b)^2 = r^2

Where:

Center= (a,b)

Radius = r

Assume that:

(a,b) = (-5,3)

r = $\sqrt{$57

The equation of the circle would be:

(x + 5)^2 + (y - 4)^2 = ($\sqrt{57$)^2

Evaluate the exponent

(x + 5)^2 + (y - 4)^2 = 57

Hence, the equation of the circle in standard form is (x + 5)^2 + (y - 4)^2 = 57

Read more about circle equations at:

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