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Reika [66]
2 years ago
5

HELP PLEASE FOR NUMER 3 and 4 PLEAESE ASAP ANI WILL GIVE BRANILESS FOR THE FIRST PERSON

Mathematics
1 answer:
jarptica [38.1K]2 years ago
6 0

Step-by-step explanation:

what number you need help with

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5. A rectangular pyramid measures three feet by four feet at the base, and has a height of seven feet. Find its volume.
den301095 [7]

Answer: 28 ft

Step-by-step explanation:

Multiply 3,4, and 7 to get 84 ft cubed. To find the volume of a pyramid, divide by 3 to get 28 ft.

4 0
3 years ago
If i have 1000 dollars and lose 1000 dollars how much do i have left 100 points
Scrat [10]

The mathematical answer would happen to be... 0

3 0
3 years ago
Read 2 more answers
Please help with 6 and 7
Maru [420]

Answer:

6a) i- 2hrs 36mins  ii- 3hrs 12mins

b) car A≈ 76.9km/h  car B≈ 62.5km/h

c)------

7a) 35km

b) car A=75km  car B=60km

c) 30km

d) car A≈36mins  car B≈48mins

Step-by-step explanation:

6a) Using the graph follow the lines until they finish then go downwards until you get to the x-axis. The x-axis is going up by 12mins for each square.

b) Using the answer from a, you divide 200km by the time.

For car A 2hrs 36mins becomes 2.6 because 36mins/60mins=0.6

∴ car A: 200/2.6≈ 76.92km/h

For car B 3hrs 12mins becomes 3.2 because 12mins/60mins=0.2

∴ car B: 200/3.2≈ 62.5km/h

7a) Using the graph go down from where the line of car A finished to meet car B. The y-axis is going up by 5km for each square.

b) Starting from the x-axis at 1 hour go upwards to see where you meet the car B line (60km) and car A line(75km). (sorry if that does not really make sense).

c) Difference from car A line to car B:

155km-125km=30km

d) Going across from 50km meet car A line and go down to see it has been travelling for approx. 36mins. Then continue across to car B line, go down to see it reached 50km at approx. 48mins.

Hope this helps.

5 0
3 years ago
Solve the following system of equations by elimination​
olya-2409 [2.1K]

Answer:

y = -6

x = 1

Step-by-step explanation:

-x + 2y = -13

-x - 2y = 11

Sum the equations:

-x -x = -2x

+2y - 2y = 0

-13 + 11 = -2

then

-2x = -2

x = -2/-2

x = 1

from the first eq.

-x + 2y = -13

-1 + 2y = -13

2y = -13 + 1

2y = -12

y = -12/2

y = -6

check:

from the second eq.

-x -2y = 11

-1 -(2*-6) = 11

-1 -(-12) = 11

-1 + 12 = 11

5 0
2 years ago
Pleeeeese help me as fast as you can!!!
Aleonysh [2.5K]

Answer:

A. y=3x-10

C. y+6=3(x-15)

Step-by-step explanation:

Given:

The given line is 6x+18y=5

Express this in slope-intercept form y=mx+b, where m is the slope and b is the y-intercept.

6x+18y=5\\18y=-6x+5\\y=-\frac{6}{18}x+\frac{5}{18}\\y=-\frac{1}{3}x+\frac{5}{18}

Therefore, the slope of the line is m=-\frac{1}{3}.

Now, for perpendicular lines, the product of their slopes is equal to -1.

Let us find the slopes of each lines.

Option A:

y=3x-10

On comparing with the slope-intercept form, we get slope as  m_{A}=3.

Now, m\times m_{A}=-\frac{1}{3}\times 3=-1. So, option A is perpendicular to the given line.

Option B:

For lines of the form x=a, where, a is a constant, the slope is undefined. So, option B is incorrect.

Option C:

On comparing with the slope-point form, we get slope as  m_{C}=3.

Now, m\times m_{C}=-\frac{1}{3}\times 3=-1. So, option C is perpendicular to the given line.

Option D:

3x+9y=8\\9y=-3x+8\\y=-\frac{3}{9}x+\frac{8}{9}\\y=-\frac{1}{3}x+\frac{8}{9}

On comparing with the slope-intercept form, we get slope as  m_{D}=-\frac{1}{3}.

Now, m\times m_{D}=-\frac{1}{3}\times -\frac{1}{3}=\frac{1}{9}. So, option D is not perpendicular to the given line.

8 0
3 years ago
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