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scZoUnD [109]
3 years ago
9

Henry mowed 37 lawns out of 60 lawns. what percent of the lawns does henry stilln need to mow

Mathematics
1 answer:
Anarel [89]3 years ago
7 0

Answer:

38 %  

Step-by-step explanation:

1. Percent of lawns mowed

\text{Percent} = \dfrac{\text{Lawns mowed}}{\text{No. of lawns}} \times 100 \% = \dfrac{37}{60} \times 100 \% = 62 \%}

2. Percent of lawns unmowed

% Unmowed = 100 % - 62 % = 38 %

Henry still needs to mow 38 % of the lawns.

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WHAT IS THE SURFACE AREA OF THE FIFURE?
max2010maxim [7]
I think the correct answer is 560ft^2.
7 0
3 years ago
Farmer Ben has only ducks and cows. He can’t remember how many of each he has, but he doesn’t need to remember because he knows
Maru [420]

Answer:

12 cows - 48 legs

4 ducks- 8 legs

- there are many different numbers you can do but if you want to change the numbers and have more ducks then: for every one cow you take away two more ducks.

Step-by-step explanation:

22 total animals

56 total legs

ducks have 2 legs

cows have 4 legs

12 times 4 = 48 ( 12 cows with 4 legs each cow =  48 legs)

4 times 2 = 8 ( 4 ducks with 2 legs each duck = 8 legs)

6 0
3 years ago
What is the value of x in the equation 3x-5=1/2x+2x
creativ13 [48]

Answer:

10

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3x−5=

1

2

x+2x

3x+−5=

1

2

x+2x

3x−5=(

1

2

x+2x)(Combine Like Terms)

3x−5=

5

2

x

3x−5=

5

2

x

Step 2: Subtract 5/2x from both sides.

3x−5−

5

2

x=

5

2

x−

5

2

x

1

2

x−5=0

Step 3: Add 5 to both sides.

1

2

x−5+5=0+5

1

2

x=5

Step 4: Multiply both sides by 2.

2*(

1

2

x)=(2)*(5)

x=10

4 0
3 years ago
An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y
aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                               P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average time = 23.92 minutes

             s = sample standard deviation = 6.72 minutes

             n = sample of times = 40

             \mu = population mean assembly time

<em> Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

<u>So, a 98% confidence interval for the population mean, </u>\mu<u> is; </u>

P(-2.426 < t_3_9 < 2.426) = 0.98  {As the critical value of z at 1%  level

                                               of significance are -2.426 & 2.426}  

P(-2.426 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.426) = 0.98

P( -2.426 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

P( \bar X-2.426 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

<u>98% confidence interval for</u> \mu = [ \bar X-2.426 \times {\frac{s}{\sqrt{n} } } , \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ]

                                     = [ 23.92-2.426 \times {\frac{6.72}{\sqrt{40} } } , 23.92+2.426 \times {\frac{6.72}{\sqrt{40} } } ]  

                                    = [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0
3 years ago
Write the exact value of the side length of each square. If the value is not a whole number, estimate the length.
Savatey [412]

Given:

The area of the squares are given.

To find:

The exact side length or estimate side length of the square.

Solution:

We know that, the area of a square is

A=a^2

Where, a is the side length of the square.

a=\sqrt{A}

Area of the square is 100 square units. So, the side length is:

a=\sqrt{100}

a=10

Therefore, the side length is 10 units.

Area of the square is 95 square units. So, the side length is:

a=\sqrt{95}

It is not exact. We know that \sqrt{81}.

Therefore, the side length is between 9 and 10.

Area of the square is 36 square units. So, the side length is:

a=\sqrt{36}

a=6

Therefore, the side length is 6 units.

Area of the square is 30 square units. So, the side length is:

a=\sqrt{30}

It is not exact. We know that \sqrt{25}.

Therefore, the side length is between 5 and 6.

8 0
3 years ago
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