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bearhunter [10]
2 years ago
8

%20if%20%5C%3A%20%20x%3Da%20%28%20%20%5CTheta%20%2B%20sin%20%20%5CTheta%20%29%20%2C%20y%3D%20a%20%281-%20Cos%20%20%5CTheta%20%29%20%5C%3A%20%20at%20%5C%3A%20%20%20%5CTheta%20%3D%20%5Cfrac%7B%CF%80%7D%7B2%7D%20%20%5C%5C%20%20%5C%5C%20%20%5C%5C%20%20%5C%5C%20%20%5C%5C%20" id="TexFormula1" title=" \sf \large \: find \: \frac{dy}{dx} \: if \: x=a ( \Theta + sin \Theta ) , y= a (1- Cos \Theta ) \: at \: \Theta = \frac{π}{2} \\ \\ \\ \\ \\ " alt=" \sf \large \: find \: \frac{dy}{dx} \: if \: x=a ( \Theta + sin \Theta ) , y= a (1- Cos \Theta ) \: at \: \Theta = \frac{π}{2} \\ \\ \\ \\ \\ " align="absmiddle" class="latex-formula">
Kindly Don't Spàm!
Thanks!!!!​
Mathematics
1 answer:
solong [7]2 years ago
4 0

<u>Given </u><u>:</u>

<u>\:  \:  \:</u>

  • \rm \large \: x = a ( \Theta + Sin  \Theta )

<u>\:  \:  \:</u>

  • \rm \large y = a ( 1 - cos   \: \Theta )

\:  \:

<u>Now , x = a ( θ + sin θ )</u>

<u>\:  \:</u>

<h3><u>Diff </u><u>w.</u><u>r</u><u>.</u><u>t</u><u> </u><u>"</u><u> </u><u>θ</u><u> </u><u>"</u></h3>

<u> </u>

<u>\:  \:  \:</u>

  • <u>\rm \large\frac{dx}{dθ }  = a \:  \frac{d}{dθ} (θ  +   \sin\theta )</u>

<u>\:  \:</u>

  • <u>\boxed{ \rm \large\underline{  \frac{dx}{d \theta} = a(1 +  \cos \theta )  }}</u>

<u>\:  \:</u>

<u>Now </u><u>y </u><u>=</u><u> </u><u>a </u><u>(</u><u> </u><u>1</u><u>-</u><u>c</u><u>o</u><u>s</u><u>θ</u><u>)</u>

<u>\:  \:</u>

<u>Diff </u><u>w.</u><u>r</u><u>.</u><u>t</u><u> </u><u>"</u><u> </u><u>θ</u><u> </u><u>"</u><u> </u><u>we </u><u>get </u><u>.</u>

<u>\:  \:</u>

  • <u>\rm \large   \frac{dy}{d \theta} = a \frac{d}{d \theta} (1 - cos \theta)</u>

<u>\:  \:  \:</u>

  • <u>\boxed{ \rm \large \underline{   \frac{dy}{d \theta} = a   \sin \theta}}</u>

<u>\:  \:  \:</u>

<u>From</u><u> </u><u>eqn </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u> </u><u>&</u><u> </u><u>(</u><u> </u><u>2</u><u> </u><u>)</u>

<u>\:  \:</u>

  • <u>\rm \large  \frac{dy}{dx}  =   \frac{ \frac{dy}{d \theta} }{\frac{dx}{d \theta}}</u>

<u>\:  \:  \:</u>

  • <u>\:  \:  \:  \rm \large =  \frac{ \cancel{a} \: sin \theta}{ \cancel a \: (1 + cos \theta)}</u>

<u>\:  \:</u>

  • <u>\rm \large \:  =  \frac{sin \theta}{1 +  \cos \theta }</u>

<u>\:  \:  \:</u>

  • <u>\rm \large \:  \frac{2 \sin( \frac{\theta }{2} ) cos\frac{\theta }{2} }{2 \: cos ^{2} \frac{\theta }{2}} \:  \:  ......(sin \: a \:  = 2 \: sin \frac{a}{2} \: cos \frac{a}{2} 1 +  \: cos \: a \:  = 2cos ^{2}  \frac{a}{2} )</u>

<u>\:  \:</u>

  • <u>\rm \large \:  \frac{dy}{dx}  =   \frac{sin \frac{ \theta}{2} }{cos  \frac{ \theta}{2} }</u>

<u>\:  \:</u>

  • <u>\rm \large \:  \frac{dy}{dx}  = tan \frac{ \theta}{2}</u>

<u>\:  \:</u>

  • <u>\rm \large \: ( \frac{dy}{dx}  )  = tan \frac{ \frac{ \theta}{2} }{2}</u>

<u>\:  \:</u>

  • <u>\rm \large \:  = tan( \frac{ \theta}{4} )</u>

<u>\:  \:</u>

  • <u>\boxed{ \rm \large \underline{ ( \frac{dy}{dx} ) =  \frac{\pi}{2}  = 1}}</u>

<u>\:  \:</u>

Hope Helps!:)

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