Answer:
x = 5/(a+3-b)
Step-by-step explanation:
ax+3x = bx+5
ax+3x-bx = 5
Take x as a common.
x(a +3 - b) = 5
x = 5/(a+3-b)
I would multiply to get rid of the decimals and work with whole numbers.
Since we have numbers that are "hundredths", we would need to multiply every number by 100.
60d + 5e = -450
-12d + 30e = 276 Now that the decimals are gone, if we multiply the second equation by 5 the "d's" will cancel.
60d + 5e = -450
-60d + 150e = 1380
155e = 930
e = 6
Now plug 6 back in for e and solve for d.
60d + 5(6) = -450
60d + 30 = -450
60d = -480
d = -8
(-8, 6)
If you'd rather work it with decimals just let me know.
Answer:
A)
2. H0: Pe = Pw
H1: Pe 
Pw
B) Test statistics 1.96
Step-by-step explanation:
Null hypothesis is a statement that is to be tested against the alternative hypothesis and then decision is taken whether to accept or reject the null hypothesis. In the given scenario the test is to identify whether there is any difference in annual goals between western division and eastern division. The null hypothesis will be the Goals of western are equal to eastern division and alternative hypothesis will be Goals of western are not equal to eastern division.
Answer:
Given that Angelo spends the same amount every day from the amount in
the lunch card, the function of the amount remaining is a linear function.
The constant rate of change of the function is; -5.25
The two ordered pairs used to find the constant rate of change are; (1, 44.75) and (2, 39.5)
Reasons:
The amount Angelo's mother put on the lunch card = $50
A possible table of values to the question is presented as follows;
Required:
The constant rate of the function that gives the amount remaining from the
amount Angelo's mother put on his lunch card.
Solution:
The two ordered pairs that can be used to find the slope or constant rate of change are;
(x₁, y₁) = (1, 44.75), and (x₂, y₂) = (2, 39.5)
With the above two ordered pairs, we have the constant rate of change of the function given as follows;
The constant rate of change for the function that gives the amount remaining in the lunch card is; -5.25
