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2 years ago

If you run 3 meters per second to the left, where will you be 4 seconds after you pass zero?

Mathematics

2 answers:

LenaWriter [7]2 years ago

7 0

Answer:

12 meters to the left, or -12

Step-by-step explanation:

3 meters per second for 4 seconds

Meaning it's 3 x 4

3 x 4 = 12, so therefore it's -12 meters or just 12 meters to the left.

bezimeni [28]2 years ago

5 0

Answer:

12 meters to the left of your starting point.

Step-by-step explanation:

You start at 0 meters. You then start running to the left with an acceleration of 3 m/s to the left. After each seconds, you are 3 more meters to the left.

3 m/s * 4 s = 12 m to the left.

Hence, the answer in 12 meters to the left.

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AlladinOne [14]

Answer:

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Step-by-step explanation:

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4 0

2 years ago

Just Need A Few Questions Answered To Finish My Quiz, Any Help Would Be Much Appreciated.

kvv77 [185]

Given the triangle

PQR

with points

P(8,0)

Q(6,2)

R(-2,-4)

And the triangle

P'Q'R'

with points

P'(4,0)

Q'(3,1)

R'(-1,-2)

Part A. Scale factor

Using the vertex

P( 8, 0)

P'(4,0)

the dilatation factor is given by

$\frac{4}{8}=\frac{1}{2}$

The triangle has a dilatation factor of 1/2

Part B:

P''Q''R'' after using P'Q'R' reflected about the y axis

to make a reflection over the y axis

coordinates (x,y) turn into coordinates (-x,y)

as follows

$P^{\prime}(4,0)\rightarrow P^{\prime\prime}(-4,0)$ $Q^{\prime}(3,1)\rightarrow Q^{\prime\prime}(-3,1)$ $R^{\prime}(-1,-2)\rightarrow R^{\prime\prime}(1,-2)$

Then triangle P''Q''R'' has coordinates

P''(-4,0)

Q''(-3,1)

R''(1,-2)

Part C:

PQR is congruent to P''Q''R''?

Congruent triangles are triangles that have the same size and shape. This means that the corresponding sides are equal and the corresponding angles are equal.

Then the triangles are not congruent