Change 5/8 to a percentage. <br> A. 87.5%<br> B. 62.5%<br> C. 92.5%<br> D. 37.5%

The stem-and-leaf plot shows the number of digs for the top 15 players at a volleyball tournament.

Tanya [424]

The data of players of volleyball tournament, the mean is 56.5, median is 53, range is 56 and interquartile range is 20

<h3>What is mean, median and mode of a data set?</h3>

The mean of the data is the average value of the given data. The mean of the data is the ratio of the sum of all the values of data to the total number of values of data.

The median of the data is the middle value of the data set when it arrange in ascending or descending order.

Mode of a data set is the value, which occurs most times for that data set. The value which has the highest frequency in the given set of data is known as the mode of that data set.

The stem-and-leaf plot shows the number of digs for the top 15 players at a volleyball tournament. The table is attached below.

The data according to the table is,

41,41,43,43,45,50,52,53,54,62,63,63,67,75,97

The mean is-

$\mu=\dfrac{41+41+43+43+45+50+52+53+54+62+63+63+67+75+97}{15}\\\mu=\dfrac{849}{15}\\\mu=56.5$

The median is.

The arranged data according to the table is,

41,41,43,43,45,50,52,53,54,62,63,63,67,75,97

Here, the middle value is 53. Thus, the median is 53.

The modes from least to greatest are , , and.

Mode is the data which occur most offen. Here the order of modes from least to greatest is,

41 41 43 43 45 50 52 53 54 62 63 63 67 75 97

The range is.

Lowest value in data is 41 and highest is 97. Thus, the range is,

$r=97-41\\r=56$

The interquartile range is.

The third quartile of data is 63 while first quartile is 43. Thus, the interquartile range is.

$IQR=63-23\\IQR=20$

Thus, the data of players of volleyball tournament, the mean is 56.5, median is 53, range is 56 and interquartile range is 20.

Learn more about the mean, median and mode here;

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4 0

1 year ago

If x is 50 then what is x4+44+3.5

lesantik [10]

The answer is: " 10,047.5 " .
_______________________________
Explanation:
________________________________
Given: " x⁴ + 44 + 3.5 " ; and given: "x = 50" ;

we can plug in "50" for "x" ; and solve:
________________________________________
10⁴ + 44 + 3.5 ;

= 10,000 + 44 + 3.5 ;

= 10,047.5
________________________________________

5 0

2 years ago

What is the slope of (-2, -1) and (-5, -9)

djyliett [7]

8/3 pretty sure that’s the answer

5 0

2 years ago

Write the slope-intercept form of the equation of the line described.

Svetach [21]

Answer:

1) y = 2/3x - 2

2) y = -1/2x + 3

Step-by-step explanation:

1) Parallel lines have the same slopes. Write it in standard form (y = mx + c), then substitute the values of the coordinates into the equation.

y = 2/3x + c

0 = 2/3(3) + c

0 = 2 + c

0 - 2 = c

- 2 = c

Therefore, the slope-intercept form for the first part is y = 2/3x - 2.

2) Parallel lines have the same slopes. Write it in standard form (y = mx + c), then substitute the values of the coordinates into the equation.

y = -1/2x + c

1 = -1/2(4) + c

1 = -2 + c

1 + 2 = c

3 = c

Therefore, the slope-intercept form for the second part is y = -1/2x + 3.

5 0

1 year ago

A study was conducted to determine whether magnets were effective in treating pain. The values represent measurements of pain us

Zanzabum

Answer:

Step-by-step explanation:

Hello!

The objective of the study is to determine whether the magnets are effective in treating pain. For these two independent groups of individuals with equal affections were randomly sampled, one was treated with magnets and the other group of individuals, call it control group, was treated with a placebo treatment.

The information for both samples is:

X₁: pain measurement using a visual analog scale after the individual received magnet treatments.

X₁~N(μ₁;σ₁²)

n₁= 20

X[bar]₁= 0.46

S₁= 0.93

X₂: pain measurement using a visual analog scale of an individual of the control groups.

X₂~N(μ₂;σ₂²)

n₂= 20

X[bar]₂= 0.41

S₂= 1.26

The claim is that the pain reductions of the control group have more variation than the pain reductions of the target group. If it's so then we could suspect that the population variance of the control group, σ₂², will be greater than the population variance of the magnet group, σ₁².

To test the relationship between these two population variances you have to conduct a variance ratio test using the Snedecors F statistic.

The hypotheses are:

H₀: σ₂² ≤ σ₁²

H₁: σ₂² > σ₁²

α: 0.05

$F= (\frac{S_2^2}{S_1^2}) * (\frac{Sigma_2^2}{Sigma_1^2} )~~ F_{(n_2-1);(n_1-1)}$

This hypothesis test is one-tailed to the right, there is only one critical value:

$F_{(n_2-1);(n_1-1); 1 - \alpha } = F_{19;19; 0.95}= 2.17$

The decision rule for the test is:

If $F_{H_0}$ ≥ 2.17, then the decision is to reject the null hypothesis.

If $F_{H_0}$ < 2.17, then the decision is to not reject the null hypothesis.

$F_{H_0}= \frac{S_2^2}{S_1^2}*\frac{Sigma_2^2}{Sigma_1^2} = \frac{(1.26)^2}{(0.93)^2} * 1$

$F_{H_0} = 1.835 = 1.84$

Since the calculated value of F is less than the critical value, the decision is to reject the null hypothesis. So using a 5% significance level the decision is to not reject the null hypothesis, you can conclude that the population variance of the pain reduction of the control group is less or equal than the population variance of the pain reduction on individuals treated with magnets.

I hope it helps!

3 0

3 years ago

Change 5/8 to a percentage. A. 87.5% B. 62.5% C. 92.5% D. 37.5%