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RSB [31]
3 years ago
5

What does negative 3 over 5 > −2 indicate about the position of negative 3 over 5 and −2 on the number line?

Mathematics
1 answer:
Gennadij [26K]3 years ago
5 0
- \dfrac 3 5 > -2

indicates - \dfrac 3 5  is to the right of -2 on the number line.
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PLEASE HELP QUICKLY. I NEED HELP!
mote1985 [20]

Answer:

4√5

Step-by-step explanation:

c = √a² + b²

c = √4² + 8²

c = √(16 + 64)

c = √80

c = 8.94427 (rounded to nearest 1/100000)

c = 4√5

8 0
3 years ago
1/2 to the 3rd power +3/2÷2/3 please show work
arsen [322]
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3 years ago
What is 2.28 x 10^-8 in standard form
Nikitich [7]
That will be -5.72 got it? It was good to help :D
4 0
3 years ago
Read 2 more answers
Approximate the answers:<br>1.5435 x 7.31<br>2.5280 x 3.211​
Zolol [24]

Answer:

<em>1)</em><em> </em><em>3</em><em>9</em><em>7</em><em>2</em><em>9</em><em>.</em><em>8</em><em>5</em>

<em>2</em><em>)</em><em>1</em><em>6</em><em>9</em><em>5</em><em>4</em><em>.</em><em>0</em><em>8</em><em> </em><em>o</em><em>r</em><em> </em><u>4</u><u>2</u><u>3</u><u>8</u><u>5</u><u>2</u>

25

Approximated answer:

<em>1</em><em>)</em><em> </em><em>4</em><em>0</em><em>0</em><em>0</em><em>0</em><em> </em><em>(</em><em>r</em><em>o</em><em>u</em><em>n</em><em>d</em><em>e</em><em>d</em><em> </em><em>o</em><em>f</em><em>f</em><em> </em><em>t</em><em>o</em><em> </em><em>t</em><em>h</em><em>o</em><em>u</em><em>s</em><em>a</em><em>n</em><em>d</em><em>)</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>o</em><em>r</em>

<em> </em><em> </em><em> </em><em> </em><em>3</em><em>9</em><em>7</em><em>3</em><em>0</em><em> </em><em>(</em><em>r</em><em>o</em><em>u</em><em>n</em><em>d</em><em>e</em><em>d</em><em> </em><em>o</em><em>f</em><em>f</em><em> </em><em>t</em><em>o</em><em> </em><em>o</em><em>n</em><em>e</em><em>)</em>

<em>2</em><em>)</em><em> </em><em> </em><em>2</em><em>0</em><em>0</em><em>0</em><em>0</em><em> </em><em>(</em><em>r</em><em>o</em><em>u</em><em>n</em><em>d</em><em>e</em><em>d</em><em> </em><em>o</em><em>f</em><em>f</em><em> </em><em>t</em><em>o</em><em> </em><em>t</em><em>h</em><em>o</em><em>u</em><em>s</em><em>a</em><em>n</em><em>d</em><em>)</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>

4 0
3 years ago
Read 2 more answers
10. WHAT is any trapezoid. A straight line
Svetradugi [14.3K]

(a) ET = 18 and WE = 12

(b) FA = 16/3

     HF = 8/3

     ET = 8

     WE = 4

<u>Explanation:</u>

WT = 30 ( WE + ET = 30)

WE = 30 - ET

2FA = 3HF

FA = 3/2HF

WE =?, ET = ?

Line WH, EF and TA are parallel to each other.

(a)

ΔWTA and ΔWHA are congruent to each other

Therefore, by congruency

                                                 \frac{WE}{ET} = \frac{HF}{FA}

So,

30 - ET/ ET = HF / 3/2HF

30 - ET / ET = 2HF / 3HF

30 - ET / ET  = 2/3

On solving the above equation we get, ET = 18

WE = 30 - ET

WE = 30 - 18 = 12

Therefore, ET = 18 and WE = 12

(b)

HA = 8 ( HF + FA = 8)

HF = 8 - FA

WT = 12 ( WE + ET = 12 )

WE = 12 - ET

GA = 2WG

HF, WA, WE, ET = ?

ΔWHA and ΔGFA are congruent

So,

\frac{HF}{FA} = \frac{WG}{GA}

8 - FA / FA = WG / 2 WG

On solving the above equation we get,

FA = 16/3

HF + FA = 8

HF + 16/3 = 8

HF = 8/3

ΔWTA and ΔWEG are congruent

So,

\frac{WE}{ET} = \frac{WG}{GA}

12 - ET / ET =  WG / 2WG

On solving the above equation, ET = 8

WE = 12 - ET

WE = 12 - 8

WE = 4

Therefore, FA = 16/3

                  HF = 8/3

                  ET = 8

                  WE = 4

7 0
3 years ago
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