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Pachacha [2.7K]
2 years ago
6

Really need help with this

Chemistry
1 answer:
DiKsa [7]2 years ago
3 0

This is a microscope.

Hope this clears that up for you.

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A 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C. If the final temperature of water is 42.0 °C, what
ludmilkaskok [199]

The initial temperature of the copper piece if a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C is 345.5°C

<h3>How to calculate temperature?</h3>

The initial temperature of the copper metal can be calculated using the following formula on calorimetry:

Q = mc∆T

mc∆T (water) = - mc∆T (metal)

Where;

  • m = mass
  • c = specific heat capacity
  • ∆T = change in temperature

According to this question, a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C. If the final temperature of water is 42.0 °C, the initial temperature of the copper is as follows:

400 × 4.18 × (42°C - 24°C) = 240 × 0.39 × (T - 24°C)

30,096 = 93.6T - 2246.4

93.6T = 32342.4

T = 345.5°C

Therefore, the initial temperature of the copper piece if a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C is 345.5°C.

Learn more about temperature at: brainly.com/question/15267055

8 0
2 years ago
 Help ASAP only right answers only no spam don’t answer if you don’t know
aliina [53]

i know the answer is a theory

6 0
3 years ago
Read 2 more answers
A 50°C solution has a pH of 3.30. At this temperature, Kw = 5.48 x 10 9. What is the pOH of the solution?
sammy [17]

Answer:

9.93

Explanation:

Your value for Kw is incorrect. The correct value is 5.48 × 10^-14.

  pH + pOH = pKw

3.30 + pOH = -log(5.84 × 10^-14) = 13.23

          pOH = 13.23 - 3.30 = 9.93

The pOH of the solution is 9.93.

4 0
3 years ago
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Divergent plate boundary is when two plates come together <br><br><br><br> True or false
Ivahew [28]

False, divergent boundaries are when two plates move away from each other.

7 0
3 years ago
Answer question number 6
Romashka [77]
It will be the first one
4 0
4 years ago
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