(a) 33.6 L of oxygen would be produced.
(b) 106 grams of
would be needed
<h3>Stoichiometric calculations</h3>
1 mole of gas = 22.4 L
(a) From the equation, 2 moles of
produce 3 moles of
. 1 mole of
will, therefore, produce 1.5 moles of
.
1.5 moles of oxygen = 22.4 x 1.5 = 33.6 L
(b) 22.4 L of
is produced at STP. This means that 1 mole of the gas is produced.
From the equation, 1 mole of
requires 1 mole of
.
Molar mass of
= (23x2)+ (12)+(16x3) = 106 g/mol
Mass of 1 mole
= 1 x 106 = 106 grams
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Explanation:
molarity = no. of moles of solute/solution in litres
molarity =0.202/7.98
=0.025 M
Answer:
LiCl because the total negative charge on Cl is one.
Explanation:
Lithium has a charge of 1+ and Chlorine has a charge of 1-.
Answer: 2.64 g of carbon dioxide that could be produced by the chemical reaction.
Explanation:
To calculate the moles :


According to stoichiometry :
1 mole of
require = 2 moles of 
Thus 0.06 moles of
will require=
of 
Thus
is the limiting reagent as it limits the formation of product and
is the excess reagent.
As 1 moles of
give = 1 mole of 
Thus 0.06 moles of
give =
of 
Mass of 
Thus 2.64 g of carbon dioxide that could be produced by the chemical reaction.