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Blizzard [7]
1 year ago
14

Which inequality is shown in the graph?

Mathematics
1 answer:
Montano1993 [528]1 year ago
6 0

Answer:

The answer is "A" i think not 100% sure

tell me if wrong

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The frequency table was made using a box containing slips of paper. Each slip of paper was numbered 0, 1, 2, 3, or 4.
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In order to make a frequency plot first we need to find the proportion of each outcome.

Total number of results = 15+20+5+5+5 = 50

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Which is a needed step to prove that AABF = AEDG?
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Answer:

\sf Since \;\sqrt{\boxed{64}}=\boxed{8}\;and\;\sqrt{\boxed{81}}=\boxed{9}\; \textsf{it is known that $\sqrt{75}$ is between}\\\\\sf \boxed{8}\;and\;\boxed{9}\;.

Step-by-step explanation:

<u>Perfect squares</u>: 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, ...

To find \sf \sqrt{75} , identify the perfect squares immediately <u>before</u> and <u>after</u> 75:

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\begin{aligned}\sf As\;\; 64 < 75 < 81\; & \implies \sf \sqrt{64} < \sqrt{75} < \sqrt{81}\\&\implies \sf \;\;\;\;\;8 < \sqrt{75} < 9 \end{aligned}

\sf Since \;\sqrt{\boxed{64}}=\boxed{8}\;and\;\sqrt{\boxed{81}}=\boxed{9}\; \textsf{it is known that $\sqrt{75}$ is between}\\\\\sf \boxed{8}\;and\;\boxed{9}\;.

See the attachment for the correct placement of \sf \sqrt{75} on the number line.

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11 months ago
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