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Phoenix [80]
3 years ago
7

Can someone help me?

Mathematics
1 answer:
ad-work [718]3 years ago
3 0

Answer:

  • registration fee: $50
  • monthly fee: $80

Step-by-step explanation:

Let r and m represent the registration fee and the monthly fee, respectively. We are told that the charges are ...

  370 = r + 4m

  530 = r + 6m

This is your system of equations.

__

Subtract the first equation from the second to start the solution.

  (530) -(370) = (r +6m) -(r +4m)

  160 = 2m . . . . . . simplify

  80 = m . . . . . . . . divide by 2

Using this value in the first equation, we find ...

  370 = r + 4(80)

  50 = r . . . . . . . . . . . . subtract 320

The registration fee is $50; the monthly fee is $80.

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Step-by-step explanation:

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Find the value of the variable y, where the sum of the fractions 6/(y+1) and y/(y-2) is equal to their product.
Blizzard [7]

Answer:

The answer is

y = 3

y =  - 4

Step-by-step explanation:

We must find a solution where

\frac{6}{y + 1}  +  \frac{y}{y - 2}  =  \frac{6}{y + 1}  \times  \frac{y}{y - 2}

Consider the Left Side:

First, to add fraction multiply each fraction on the left by it corresponding denomiator and we should get

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Simplify the right side by multiplying the fraction

\frac{6y}{(y  + 1)(y + 2)}

Set both fractions equal to each other

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Since the denomiator are equal, we must set the numerator equal to each other

6y =  {y}^{2}  + 7y - 12

=  {y}^{2}  + y - 12

(y  + 4)(y - 3)

y =  - 4

y = 3

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