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Nutka1998 [239]
2 years ago
14

Find the equation (in the terms of x) of the line through the points (-2,-5) and (5,0)

Mathematics
1 answer:
Alex_Xolod [135]2 years ago
3 0

Answer:

-5x+7y+25=0

Step-by-step explanation:

vecto AB= (7;5)

vecto n = (-5;7)

line through the points (-2;5) and (5;0) :

-5*(x+2)+7*(y+5)=0

-5x+7y+25=0

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Use the information provided to write the equation of the circle Center: (10,-9) Point on Circle: (12,-13)
Zielflug [23.3K]

Answer:

(x - 10)² + (y + 9)² = 20

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

The radius is the distance from the centre to a point on the circle

To calculate r use the distance formula

r = √(x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (10, - 9) and (x₂, y₂ ) = (12, - 13)

r = \sqrt{(12-10)^2+(-13+9)^2}

  = \sqrt{4+16} = \sqrt{20}, hence

(x - 10)² + (y - (- 9))² = (\sqrt{20})², that is

(x - 10)² + (y + 9)² = 20

7 0
3 years ago
Solve for y . =−5y-15=35
4vir4ik [10]
-5y-15=35 \\ -5y=35+15 \\ -5y=50 /:5\\ -y=10 \\ y=-10
3 0
3 years ago
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The coordinate grid below shows triangle ABC and its image after translation, triangle A'B'C': Triangles ABC and A prime B prime
stira [4]

Answer:

the answer is y - 8

Step-by-step explanation:

just makes sense

3 0
3 years ago
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Find the distance<br> between the points:<br> (-5, 7) and (4, -2)
bonufazy [111]

Answer:

d = 9√2

Step-by-step explanation:

d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}\\\\d=\sqrt{\left(4-\left(-5\right)\right)^2+\left(-2-7\right)^2}\\\\d=\sqrt{\left(4+5\right)^2+\left(-2-7\right)^2}\\\\d=\sqrt{9^2+9^2}\\\\\mathrm{Add\:similar\:elements:}\:9^2+9^2=9^2\times\:2\\\\=\sqrt{9^2\times\:2}\\\\=\sqrt{2}\sqrt{9^2}\\\\=9\sqrt{2}

7 0
3 years ago
Another one. Find the gradients of the lines A and B.
GREYUIT [131]

Answer:

Step-by-step explanation:

Gradient of a line is the same as slope of the line. Slope is defined as the ratio of the rate of change in the y(vertical) axis to the rate of change in the x(horizontal) axis.

Slope = (y2 - y1)/(x2 - x1)

Slope is denoted by m. Therefore,

For line A,

y1 = - 1

y2 = 3

x1 = 2

x2 = 3

Slope, m = (3 - - 1)/((3 - 2) = 4/1 = 4

For line B,

y1 = 5

y2 = 1

x1 = - 2

x2 = 0

Slope, m = (1 - 5)/((0 - - 2) = - 4/2 = - 2

4 0
3 years ago
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