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2 years ago

Simplify the monomials

Mathematics

1 answer:

Tomtit [17]2 years ago

7 0

Answer:

1. $-12x^{5}y^{5}$

2. $\frac{10b^{8} }{a^{3} }$

3. correct

4. $a^{8}b^{10}c^{15}$

Step-by-step explanation:

When dividing a monomial by another monomial, we divide the coefficients and apply the quotient law of exponents, x m ÷ x n = x m – n to the variables. If both the monomials have negative coefficients, the negative signs cancel out and the answer so obtained will be having a positive coefficient only.

For example, the binomial 2x +4 can be multiplied by the monomial 4x so that (2x) (4x) equals 8x2 and 4·4x equals 16x, using the distributive property. Therefore, (2x +4) (4x) equals 8x2 + 16x.Mar 15, 2016

Use the Quotient Property. When we divide monomials with more than one variable, we write one fraction for each variable. Use fraction multiplication. Simplify and use the Quotient Property.

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3 years ago

A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and

nasty-shy [4]

Answer:

correct option is C) 2.8

Step-by-step explanation:

given data

string vibrates form = 8 loops

in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

$l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}$

and we know velocity is express as

velocity = frequency × wavelength .....................2

$\sqrt{\frac{Tension}{mass\ per\ unit \length }}$ = f × $\lambda_1$

here tension = mg

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

and

case (2)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

$l = \frac{10 \lambda _1}{2}$ ..............4

$l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}$

when block is immersed

equilibrium eq will be

Tenion + force of buoyancy = mg

T + v × $\rho$ × g = mg

and

T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

relative density $\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}$

relative density = 2.78 ≈ 2.8

so correct option is C) 2.8

3 0

3 years ago

Two trains leave stations 288 miles apart at the same time and travel towards each other. One train travels at 95 miles per hour

erma4kov [3.2K]

95x=85x+288
You could add 288 to any side, it just shows that they're 288 miles apart.
Let's subtract 85x from both sides.
10x=288
28.8=x
It'll take 28.8 hours for the trains to meet. Let's make sure.
28.8×95
2,736
28.8×85
2,448
2,736-2,448
288
So, they'll meet up after 28.8 miles.

5 0

2 years ago

Please help asap!!! 19 pts

wlad13 [49]

The correct answer is b

7 0

3 years ago

Solve the equation thanks!

AlladinOne [14]

Answer:

c = $\frac{27}{40}$