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3 years ago

Simplify the monomials

Mathematics

1 answer:

Tomtit [17]3 years ago

7 0

Answer:

1. $-12x^{5}y^{5}$

2. $\frac{10b^{8} }{a^{3} }$

3. correct

4. $a^{8}b^{10}c^{15}$

Step-by-step explanation:

When dividing a monomial by another monomial, we divide the coefficients and apply the quotient law of exponents, x m ÷ x n = x m – n to the variables. If both the monomials have negative coefficients, the negative signs cancel out and the answer so obtained will be having a positive coefficient only.

For example, the binomial 2x +4 can be multiplied by the monomial 4x so that (2x) (4x) equals 8x2 and 4·4x equals 16x, using the distributive property. Therefore, (2x +4) (4x) equals 8x2 + 16x.Mar 15, 2016

Use the Quotient Property. When we divide monomials with more than one variable, we write one fraction for each variable. Use fraction multiplication. Simplify and use the Quotient Property.

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3 years ago

Squareroot(y-1) + 3 = y

jek_recluse [69]

Note:xy means x times y and x(y) means the same thing

so
first we get rid of square root then
make the equation equal to zero becaues if
xy=0 then x or/and y=0

squareroot(y-1)+3=y

isolate the squareroot
subtrac 3 from boht sides

squareroot(y-1)=y-3

square both sides (since they are equal, you should be able to square both sides and still make it true)

(squareroot(y-1))^2=(y-3)^2
(y-1)=(y-3)(y-3)
y-1=y^2-6y+9
subtrac y from both sides
-1=y^2-7y+9
add 1 to both sides
0=y^2-7y+10
find what two number multiply to make 10 and add to get -7
the answer is -2 and -5

0=(y-5)(y-2)
therfore
y-5=0
and/or
y-2=0

therefor
y=5 or/and 2 might work
let's try out 2
square root(2-1)+3=2
square root(1)+3=2
1+3=2
false
so 2 doesn't work

let's try 5
squareroot(5-1)+3=5
squareroot(4)+3=5
2+3=5
5=5
true

y=5

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Read 2 more answers