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2 years ago

Pls helpppppppppppppppppppppp

Mathematics

2 answers:

Arada [10]2 years ago

5 0

Answer:

Both of them are correct because if we simply the fraction of Edwin we will get the fraction of Tony

$\frac{3}{6}$

$= \frac{1}{2}$

PLEASE MARK ME BRAINLIEST IF MY ANSWER IS CORRECT PLEASE

QveST [7]2 years ago

3 0

Both are actually correct.

This is because the dice has 6 different sides, which means it has a variation on 6. Since there is only 3 even numbers you could say there is a probability of 3/6. So Edwin is right, but if you simplify 3/6 you get 1/2 so Tony is also right.

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MATH QUESTION!! WILL MARK BRAINLIEST!! PAST DUE HELP ASAP!!!

monitta

Answer:

<em>Proof below</em>

Step-by-step explanation:

<u>Right Triangles</u>

In any right triangle, i.e., where one of its internal angles is 90°, some interesting relations stand. One of the most-used is Pythagora's Theorem.

In a right triangle with shorter sides a and b, and longest side c, called the hypotenuse, the following equation is satisfied:

$c^2=a^2+b^2$

The image provided in the question shows a line passing through points A(0,4) and B(3,0) that forms a right triangle with both axes.

The origin is marked as C(0,0) and the point M is the midpoint of the segment AB. We have to prove.

$CM=\frac{1}{2}AB$

First, find the coordinates of the midpoint M(xm,ym):

$\displaystyle x_m=\frac{0+3}{2}=1.5$

$\displaystyle y_m=\frac{4+0}{2}=2$

Thus, the midpoint is M( 1.5 , 2 )

Calculate the distance CM:

$CM=\sqrt{(1.5-0)^2+(2-0)^2}$

$CM=\sqrt{2.25+4}=\sqrt{6.25}=2.5$

CM=2.5

Now find the distance AB:

$AB=\sqrt{(3-0)^2+(4-0)^2}=\sqrt{3^2+4^2}=\sqrt{9+16}=\sqrt{25}$

AB=5

AB/2=2.5

It's proven CM is half of AB

3 0

3 years ago

This section of a concrete skateboard ramp has the shape of a triangular prism. Find the volume of the triangular prism. Find th

NISA [10]

Answer:

The volume of the triangular prism: 59.2 $ft^{3}$

The value of the concrete used is: 16*4 = $64

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one. Please have a look at the attached photo

My answer:

As we know that, the formula to find out the volume of the triangular prism is:

V = $\frac{1}{2} a*b*h$ when h is the height and a&b are the length of the two square edges. So we have:

V = $\frac{1}{2}$ *4*4*7.4 = 59.2 $ft^{3}$

To find the concrete used in the ramp if the cost of concrete is $ 4.00 per cubic foot, we need to know the area of the ramp, which is:

S = 4*4 = 16 $ft^{2}$

Hence, the value of the concrete used is: 16*4 = $64

8 0

3 years ago

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ABCD×9=DCBA<br>(what is the value of A, B, C and D)

Anettt [7]

Answer:

Step-by-step explanation:

The only value that would make sense is if at least one of the variables (A , B , C , D) is 0 (if not all of them). When multiplied, the answer will still be 0, thereby making the equation true.

4 0

3 years ago

Let X be a set of size 20 and A CX be of size 10. (a) How many sets B are there that satisfy A Ç B Ç X? (b) How many sets B are

Svetlanka [38]

Answer:

(a) Number of sets B given that

A⊆B⊆C: 2¹⁰. (That is: A is a subset of B, B is a subset of C. B might be equal to C)
A⊂B⊂C: 2¹⁰ - 2. (That is: A is a proper subset of B, B is a proper subset of C. B≠C)

(b) Number of sets B given that set A and set B are disjoint, and that set B is a subset of set X: 2²⁰ - 2¹⁰.

Step-by-step explanation:

Let $x_1, x_2, \cdots, x_{20}$ denote the 20 elements of set X.

Let $x_1, x_2, \cdots, x_{10}$ denote elements of set X that are also part of set A.

For set A to be a subset of set B, each element in set A must also be present in set B. In other words, set B should also contain $x_1, x_2, \cdots, x_{10}$ .

For set B to be a subset of set C, all elements of set B also need to be in set C. In other words, all the elements of set B should come from $x_1, x_2, \cdots, x_{20}$ .

$\begin{array}{c|cccccccc}\text{Members of X} & x_1 & x_2 & \cdots & x_{10} & x_{11} & \cdots & x_{20}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set A?} & \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{No} & \cdots & \text{No}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set B?}& \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{Maybe} & \cdots & \text{Maybe}\end{array}$ .

For each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus $2^{10} = 1024$ possibilities for set B.

In case the question connected set A and B, and set B and C using the symbol ⊂ (proper subset of) instead of ⊆, A ≠ B and B ≠ C. Two possibilities will need to be eliminated: B contains all ten "maybe" elements or B contains none of the ten "maybe" elements. That leaves $2^{10} -2 = 1024 - 2 = 1022$ possibilities.

Set A and set B are disjoint if none of the elements in set A are also in set B, and none of the elements in set B are in set A.

Start by considering the case when set A and set B are indeed disjoint.

$\begin{array}{c|cccccccc}\text{Members of X} & x_1 & x_2 & \cdots & x_{10} & x_{11} & \cdots & x_{20}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set A?} & \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{No} & \cdots & \text{No}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set B?}& \text{No}&\text{No}&\cdots &\text{No}& \text{Maybe} & \cdots & \text{Maybe}\end{array}$ .

Set B might be an empty set. Once again, for each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus $2^{10} = 1024$ possibilities for a set B that is disjoint with set A.

There are 20 elements in X so that's $2^{20} = 1048576$ possibilities for B ⊆ X if there's no restriction on B. However, since B cannot be disjoint with set A, there's only $2^{20} - 2^{10}$ possibilities left.

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3 years ago

A family gathered 20 small seashells from the beach bringing the total number of small seashells in their collection to 41.

Aleks [24]

7 in a half because your non

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2 years ago

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