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Vikentia [17]
3 years ago
9

Solving a right triangle (round to the nearest tenth)

Mathematics
1 answer:
Inga [223]3 years ago
5 0

Answer:

see explanation

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the given angles from 180 for A

A = 180° - (90 + 46)° = 180° - 136° = 44°

----------------------------------------------------------------

tan46° = \frac{opposite}{adjacent} = \frac{b}{23}

Multiply both sides by 23

23 × tan46° = b, thus

b ≈ 23.8 ( to the nearest tenth )

-----------------------------------------------------------------

cos46° = \frac{adjacent}{hypotenuse} = \frac{23}{c}

Multiply both sides by c

c × cos46° = 23 ( divide both sides by cos46° )

c = \frac{23}{cos46} ≈ 33.1 ( to the nearest tenth )

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