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3 years ago

9

Solving a right triangle (round to the nearest tenth)

1 answer:

Inga [223]3 years ago

5 0

Answer:

see explanation

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the given angles from 180 for A

A = 180° - (90 + 46)° = 180° - 136° = 44°

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tan46° = $\frac{opposite}{adjacent}$ = $\frac{b}{23}$

Multiply both sides by 23

23 × tan46° = b, thus

b ≈ 23.8 ( to the nearest tenth )

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cos46° = $\frac{adjacent}{hypotenuse}$ = $\frac{23}{c}$

Multiply both sides by c

c × cos46° = 23 ( divide both sides by cos46° )

c = $\frac{23}{cos46}$ ≈ 33.1 ( to the nearest tenth )

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