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NNADVOKAT [17]
2 years ago
7

help me please. I'll give brainly, thank u >>>>>>>>>>>>>>>>>>>>>&

gt;>>>>>>>>>>>>>>>>

Mathematics
1 answer:
Arada [10]2 years ago
6 0

Answer:

a

Step-by-step explanation:

the solution to the system is at the point of intersection of the linear equations.

the lines intersect at (- 4, 3 )

then solution is (- 4, 3 )

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At the time she had $237 ,the cost of a lesson rose to &19.how many lesson can she pay for with remaining &237
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12.5, just divide 237 by 19
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Kazeer [188]
The answer is C, point P
4 0
2 years ago
A figure has vertices at points (0,3),(6,3), and (3,6)what polygon is made
VladimirAG [237]

Answer:

The polygon that is made is a triangle

Step-by-step explanation:

5 0
3 years ago
If bolt thread length is normally distributed, what is the probability that the thread length of a randomly selected bolt is Wit
KatRina [158]

Answer:

a) 0.5762

b) 0.0214

c) 0.2718

Step-by-step explanation:

It is given that lengths of the bolt thread are normally distributed. So in order to find the required probability we can use the concept of z distribution and z scores.

Part a) Probability that length is within 0.8 SDs of the mean

We have to calculate the probability that the length of a bolt thread is within 0.8 standard deviations of the mean. Recall that a z- score tells us that how many standard deviations away a value is from the mean. So, indirectly we are given the z-scores here.

Within 0.8 SDs of the mean, means from a score of -0.8  to +0.8. i.e. we have to calculate:

P(-0.8 < z < 0.8)

We can find these values from the z table.

P(-0.8 < z < 0.8) = P(z < 0.8) - P(z < -0.8)

= 0.7881 - 0.2119

= 0.5762

Thus, the probability that the thread length of a randomly selected bolt is within 0.8 SDs of its mean value is 0.5762

Part b) Probability that length is farther than 2.3 SDs from the mean

As mentioned in previous part, 2.3 SDs means a z-score of 2.3.

2.3 Standard Deviations farther from the mean, means the probability that z scores is lesser than - 2.3 or greater than 2.3

i.e. we have to calculate:

P(z < -2.3 or z > 2.3)

According to the symmetry rules of z-distribution:

P(z < -2.3 or z > 2.3) = 1 - P(-2.3 < z < 2.3)

We can calculate P(-2.3 < z < 2.3) from the z-table, which comes out to be 0.9786. So,

P(z < -2.3 or z > 2.3) = 1 - 0.9786

= 0.0214

Thus, the probability that a bolt length is 2.3 SDs farther from the mean is 0.0214

Part c) Probability that length is between 1 and 2 SDs from the mean value

Between 1 and 2 SDs from the mean value can occur both above the mean and below the mean.

For above the mean: between 1 and 2 SDs means between the z scores 1 and 2

For below the mean: between 1 and 2 SDs means between the z scores -2 and -1

i.e. we have to find:

P( 1 < z < 2) + P(-2 < z < -1)

According to the symmetry rules of z distribution:

P( 1 < z < 2) + P(-2 < z < -1) = 2P(1 < z < 2)

We can calculate P(1 < z < 2) from the z tables, which comes out to be: 0.1359

So,

P( 1 < z < 2) + P(-2 < z < -1) = 2 x 0.1359

= 0.2718

Thus, the probability that the bolt length is between 1 and 2 SDs from its mean value is 0.2718

4 0
3 years ago
Use natural logarithms to solve the equation. Round to the nearest thousandth. 3e^2x +5=27
puteri [66]

Answer:

x=0.996

Step-by-step explanation:

3e^{2x} +5=27

To take natural log ln , we need to get e^2x alone

Subtract 5 on both sides

3e^{2x}=22

Now we divide both sides by 3

e^{2x}=\frac{22}{3}

Now we take 'ln' on both sides

ln(e^{2x})=ln(\frac{22}{3})

As per log property we can move exponent 2x before ln

(2x)ln(e)=ln(\frac{22}{3})

The value of ln(e) = 1

2x=ln(\frac{22}{3})

Divide both sides by 2

x=\frac{ln(\frac{22}{3})}{2}

x= 0.996215082

Round to nearest thousandth

x=0.996

6 0
3 years ago
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