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4 years ago

Determine the coefficient of the term “-15x”

Mathematics

2 answers:

Sergio039 [100]4 years ago

7 0

-15 because -15x is the variable term

Anna007 [38]4 years ago

3 0

Answer:

Step-by-step explanation:

The "coefficient" of x here is -15.

"determine the coefficient of the term “-15x” " is not a valid question.

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Which value is a solution to the inequality x – 4 > 15.5? A. X = 17.3 B. X = 21.4 C. X = 15.5 D. X = 19.3

Dvinal [7]

x-4>15.5

x>15.5+4

x>19.5

i suppose the answer is D since it is the closest to ^.

8 0

3 years ago

Anthony asked a group of students to choose their favorite type of music from the choices of rock, hip-hop, and country. The res

Fudgin [204]

Answer:

240

Step-by-step explanation:

add up the numbers of all the students that were surveyed

get 90

60 of those were rock or hiphop

divide 360 by 90

get 4

multiply 60 by 4

get 240

8 0

3 years ago

Sarah uses a recipe to make 2 gallons of juice. Two of the containers she plans to use to store the juice have a capacity of one

Allisa [31]

Answer:

14 pint containers.

Step-by-step explanation:

First we have to convert gallon to quart.

2 gallons = 8 quarts

There are 2 containers that added up to 1 quart, so let's subtract the one quart from the 2 gallons(8 quarts), leaving behind 7 quarts.

The conversion between quarts and pints are 1qt=2pt, according to the key you provided. Then 7 quarts will equal to 14 pints. And therefore, she will need 14 pint containers.

4 0

3 years ago

If y=1/2 when x=2, find y when x=3, given that y varies directly with x

Lelu [443]

$\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\
\textit{we also know that }
\begin{cases}
y=\frac{1}{2}\\
x=2
\end{cases}\implies \cfrac{1}{2}=k2\implies \cfrac{1}{4}=k
\\\\\\
\boxed{y=\cfrac{1}{4}x}
\\\\\\
\textit{when x=3, what is \underline{y}?}\qquad y=\cfrac{1}{4}\cdot 3$

4 0

3 years ago

Suppose that a large mixing tank initially holds 100 gallons of water in which 50 pounds of salt have been dissolved. Another br

Serggg [28]

Answer:

dA/dt = 12 - 2A/(100 + t)

Step-by-step explanation:

The differential equation of this problem is;

dA/dt = R_in - R_out

Where;

R_in is the rate at which salt enters

R_out is the rate at which salt exits

R_in = (concentration of salt in inflow) × (input rate of brine)

We are given;

Concentration of salt in inflow = 4 lb/gal

Input rate of brine = 3 gal/min

Thus;

R_in = 4 × 3 = 12 lb/min

Due to the fact that solution is pumped out at a slower rate, thus it is accumulating at the rate of (3 - 2)gal/min = 1 gal/min

So, after t minutes, there will be (100 + t) gallons in the tank

Therefore;

R_out = (concentration of salt in outflow) × (output rate of brine)

R_out = [A(t)/(100 + t)]lb/gal × 2 gal/min

R_out = 2A(t)/(100 + t) lb/min

So, we substitute the values of R_in and R_out into the Differential equation to get;

dA/dt = 12 - 2A(t)/(100 + t)

Since we are to use A foe A(t), thus the Differential equation is now;

dA/dt = 12 - 2A/(100 + t)

5 0

3 years ago