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likoan [24]
2 years ago
5

Solve the following equation: 3 x seven tenths

Mathematics
1 answer:
djverab [1.8K]2 years ago
5 0
<h3>hello!</h3>

=================================================

Here, we have to multiply fractions.

How to Multiply Fractions?

Here are the steps:-

<u />

  • Turn any whole numbers into fractions (example:- 3 = 3/1)
  • Multiply the numerator of the first fraction times the numerator of the 2nd fraction; same with the denominator.
  • Simplify if necessary.

So let's do it.

Step 1:-

\longmapsto\sf{3=\displaystyle\frac{3}{1}

Step 2:-

\longmapsto\sf{\displaystyle\frac{3}{1} *\frac{7}{10}}

\longmapsto\sf{\displaystyle\frac{21}{10} }

We can't simplify this fraction, but there's something else we can do:-

  • Convert this improper fraction into a mixed number

Here's the answer:-

\boxed{\sf{2\displaystyle\frac{1}{10} }}

=====================================================

<h3>note:-</h3>

Hope everything is clear; if you need any explanation/clarification, kindly let me know, and I will comment and/or edit my answer :)

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Please give me a hand
Westkost [7]

Answer:

2

Step-by-step explanation:

7x - 2x = 13 - 3

5x = 10

x = 2

7 0
3 years ago
Read 2 more answers
You are planning a May camping trip to Denali National Park in Alaska and want to make sure your sleeping bag is warm enough. Th
Goshia [24]

The probability that this bag will be warm enough on a randomly

selected May night at the park is 0.8106 ⇒ answer C

Step-by-step explanation:

You are planning a May camping trip to Denali National Park in Alaska

and want to make sure your sleeping bag is warm enough.

The average low temperature in the park for May follows a normal

distribution

The given is:

1. The mean is 32°F

2. The standard deviation is 8°F

3. One sleeping bag you are considering advertises that it is good for

   temperatures down to 25°F (x ≥ 25)

At first let us find the z-score

∵ z = (x - μ)/σ, where x is the score, μ is the mean, σ is standard deviation

∵ μ = 32°F , σ = 8°F , x = 25°F

- Substitute these values in the rule

∴ z = \frac{25-32}{8}=-0.875

Now let us find the corresponding area of z-score in the normal

distribution table

∵ The corresponding area of z = -0.875 is 0.18943

∵ For P(x ≥ 25) the area to the right is needed

∵ P(x ≥ 25) = 1 - 0.18943 = 0.8106

∴ P(x ≥ 25) = 0.8106

The probability that this bag will be warm enough on a randomly

selected May night at the park is 0.8106

Learn more:

You can learn more about mean and standard deviation in brainly.com/question/6073431

#LearnwithBrainly

3 0
3 years ago
Which of the following values are solutions to the inequality - 8 - 3x &gt; 2?
____ [38]

Isolate the variable by dividing each side by factors that don't contain the variable.

Inequality Form:

X< -10/3

Interval Notation:

(-∞, - 10/3)

Hope this is right :)

6 0
3 years ago
A jar contains 4 blue marbles, 6 red marbles, 10 purple
earnstyle [38]

Answer:

A

Step-by-step explanation

I got the right answer

4 0
3 years ago
businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
3 years ago
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