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GrogVix [38]
3 years ago
9

Pls need help asap!!!

Mathematics
1 answer:
Sloan [31]3 years ago
8 0

Trigonometry is the branch of mathematics that studies the relationship between the sides lengths and angles in a triangle.

<h3>What is trigonometry?</h3>

Your information is incomplete as the triangles aren't given. Therefore, an overview will be given.

It should be noted that trigonometry simply means the branch of mathematics that is concerned with angles and their application to calculation.

In this case, studies the relationship between the sides lengths and angles in a triangle. The there basic functions in trigonometry are sine, cosine, ad tangent.

Learn more about trigonometry on:

brainly.com/question/24236629

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Determine the value of x in the figure. Question 1 options: A) x = 90 B) x = 85 C) x = 45 D) x = 135
Anna35 [415]

Answer:

A.) x=90°

Step-by-step explanation:

Note:

The triangle shown is an isosceles triangle, which means that it has 2 congruent sides (as shown by the small intersecting lines), and this also means that it has two congruent angles.

We are given an angle measure adjacent to one of the missing angles. These two form supplementary angles, which means that they're sum is equal to 180°, or a straight line. So, to find:

180=135+y

y is the unknown angle. Solve for y:

180-135=y\\\\y=45

y is 45°. Since this and the other angle are congruent, add:

45+45=90

Note:

Triangles angles will always add up to a total of 180°.

To find the missing angle x°, use:

180=a+b+c

These are the angles in a triangle. Substitute any known values and solve:

180=45+45+x\\\\180=90+x\\\\180-90=x\\\\x=90

The missing angle x° is 90°.

:Done

3 0
4 years ago
The graph of a line passes through the points (0,-2) and (6,0). What is the equation of the line?
Dima020 [189]

Answer:

y=1/3x-2

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(0-(-2))/(6-0)

m=(0+2)/6

m=2/6

simplify

m=1/3

y-y1=m(x-x1)

y-(-2)=1/3(x-0)

y+2=1/3(x)

y+2=1/3x

y=1/3x-2

6 0
3 years ago
A jar contains 12 red marbles numbered 1 to 12 and 6 blue marbles numbered 1 to 6. A marble is drawn at random from the jar. Fin
lora16 [44]

Answer:

(a)P(Red)=\dfrac{2}{3}\\(b)P(Odd) =\dfrac{1}{2}\\(c)P(\text{Red or Odd Numbered})=\dfrac{5}{6}\\(d)P(\text{Blue or Even Numbered})=\dfrac{2}{3}

Step-by-step explanation:

Number of Red Marbles{1,2,3,4,5,6,7,8,9,10,11,12},n(R)=12

Number of Blue Marbles{1,2,3,4,5,6},n(B)=6

Total Number of Marbles, n(S)=6+12=18

(a)Probability that the Marble is Red

P(R)=\dfrac{n(R)}{n(S)} =\dfrac{12}{18} =\dfrac{2}{3}

(b)Probability that the marble is odd-numbered.

Number of Odd-Numbered Balls, n(O)=9

P(Odd)=\dfrac{n(O)}{n(S)} =\dfrac{9}{18} =\dfrac{1}{2}

(c)Probability that the marble is red or odd-numbered.

n(Red)=12

n(Odd Numbered marbles)=9

n(Red and Odd Numbered Marbles)=6

P(\text{Red or Odd Numbered})=P(Red)+P(Odd\:Numbered)-P(\text{Red and Odd Numbered)}\\=\dfrac{12}{18} +\dfrac{9}{18}-\dfrac{6}{18}  =\dfrac{15}{18}\\P(\text{Red or Odd Numbered})=\dfrac{5}{6}(d)Probability that the marble is blue or even-numbered.

n(Blue)=6

n(Even Numbered marbles)=9

n(Blue and Even Numbered Marbles)=3

P(\text{Blue or Even Numbered})=P(Blue)+P(Even\:Numbered)-P(\text{Blue and Even Numbered)}\\=\dfrac{6}{18} +\dfrac{9}{18}-\dfrac{3}{18}  =\dfrac{12}{18}\\P(\text{Blue or Even Numbered})=\dfrac{2}{3}

5 0
3 years ago
Write a problem that involves finding the unknown measure of a side of a rectangle include the solution?
tankabanditka [31]
Problem:
 The area of the patio of a relative's house is 20 square meters.
 The width of the patio is 2 meters.
 What is the length of the patio?
 Solution:
 
The area is:
 A = (w) * (l)
 Where,
 w: width
 l: long
 Clearing l we have:
 l = A / w
 Substituting values:
 l = 20/2
 l = 10 meters
7 0
3 years ago
Victor has saved $89.25 for the bicycle that he wants. The bicycle costs $129.85. Victor
zubka84 [21]

Answer:

he should set up the problem so he can find the amount he has left to save. so 129.85 - 89.25 = X or the amount he needs.

he could also do 89.25 + X = 129.85

3 0
4 years ago
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