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vredina [299]
3 years ago
5

Is this function linear or nonlinear? *

Mathematics
2 answers:
Orlov [11]3 years ago
6 0

Answer:

Step-by-step explanation:

a function representing a st. line is linear.

Bogdan [553]3 years ago
5 0

Answer:

It's linear

Step-by-step explanation:

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Which of the following answer choices is an equation for the circle with a center of (-2, 3) and a radius of 3?
mamaluj [8]

Answer:

A

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k) = (- 2, 3) and r = 3 , then

(x + 2)² + (y - 3)² = 9 ← expand left side using FOIL

x² + 4x + 4 + y² - 6y + 9 = 9  ( subtract 9 from both sides )

x² + y² + 4x - 6y + 4 = 0 → A

5 0
2 years ago
The vertex formation of a parabola is x = 8(y- 1)2-76.
Gennadij [26K]

Answer:

\boxed{x=8y^2-16y-68}

Step-by-step explanation:

Hello, please consider the following.

x=8(y- 1)^2-76\\\\x=8(y^2-2y+1)-76\\\\x=8y^2-16y+8-76\\\\\boxed{x=8y^2-16y-68}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

6 0
3 years ago
Read 2 more answers
PLEASE ANSWER + BRAINLIEST!!<br><br> Factor completely.<br><br> 4k - 20k^9 =<br><br> 3b^2 - 108 =
Neporo4naja [7]
4k-20k^9=4k(1-5k^8)=4k\left[1^2-(k^4\sqrt5)^2\right]\\\\=4k(1-k^4\sqrt5)(1+k^4\sqrt5)=4k\left[1^2-(k^2\sqrt[4]5)^2\right](1+k^4\sqrt5)\\\\=4k(1-k^2\sqrt[4]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k\left[1^2-(k\sqrt[8]5)^2\right](1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k(1-k\sqrt[8]5)(1+k\sqrt[8]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)

3b^2-108=3(b^2-36)=3(b^2-6^2)=3(b-6)(b+6)

Used:\ (a-b)(a+b)=a^2-b^2
7 0
3 years ago
If there is a 70% chance of rain tomorrow and a 50% chance of wind and rain,
enyata [817]

Answer:

71%

Step-by-step explanation:

Conditional Probability: <u>P(A and B)</u>

                                            P(A)

P(A and B): 0.5

P(A): 0.7

=0.5/0.7

=0.71428... (x 100)

4 0
3 years ago
Read 2 more answers
A certain paper suggested that a normal distribution with mean 3,500 grams and a standard deviation of 560 grams is a reasonable
Natalka [10]

Answer: the probability that a randomly selected Canadian baby is a large baby is 0.19

Step-by-step explanation:

Since the birth weights of babies born in Canada is assumed to be normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = birth weights of babies

µ = mean weight

σ = standard deviation

From the information given,

µ = 3500 grams

σ = 560 grams

We want to find the probability or that a randomly selected Canadian baby is a large baby(weighs more than 4000 grams). It is expressed as

P(x > 4000) = 1 - P(x ≤ 4000)

For x = 4000,

z = (4000 - 3500)/560 = 0.89

Looking at the normal distribution table, the probability corresponding to the z score is 0.81

P(x > 4000) = 1 - 0.81 = 0.19

5 0
3 years ago
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